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1 year ago

A rectangular prism has a length of 13ft and a width of 16ft.

Mathematics

1 answer:

IrinaK [193]1 year ago

8 0

Considering the volume of the rectangular prism, it is found that it's height is of 4.5 ft.

<h3>What is the volume of a rectangular prism?</h3>

The volume of a rectangular prism of length l, width w and height h is given by:

$V = lwh$

In this problem, the measures given are as follows:

l = 13 ft, w = 16 ft, V = 936 ft³.

Hence, the height, in ft, is found as follows:

$V = lwh$

$13 \times 16 \times h = 936$

$h = \frac{936}{13 \times 16}$

$h = 4.5$

More can be learned about the volume of a rectangular prism at brainly.com/question/17223528

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10. Write a word problem for this equation:<br> n ($25) = $125

Andrei [34K]

Answer:

The word problem is "How many $25 are there in $125?"

Step-by-step explanation:

Given

$n(\$25) = \$125$

Required

Write a word problem for the expression

We start by solving the given equation

$n(\$25) = \$125$

Divide both sides by $25

$\frac{n(\$25)}{\$25} = \frac{\$125}{\$25}$

$n = \frac{\$125}{\$25}$

$n = 5$

This implies that there are 5, $25 in $125

<em>Hence; The word problem is "How many $25 are there in $125?"</em>

6 0

3 years ago

Detmermine the best method to solve the following equation, then solve the equation. (3x-5)^2=-125

liq [111]

For the given equation;

$(3x-5)^2=-125$

We shall begin by expanding the parenthesis on the left side, after which we would combine all terms on and move all of them to the left side, which shall yield a quadratic equation. Then we shall solve.

Let us begin by expanding the parenthesis;

$\begin{gathered} (3x-5)^2\Rightarrow(3x-5)(3x-5) \\ (3x-5)(3x-5)=9x^2-15x-15x+25 \\ (3x-5)^2=9x^2-30x+25 \end{gathered}$

Now that we have expanded the left side of the equation, we would have;

$\begin{gathered} 9x^2-30x+25=-125 \\ \text{Add 125 to both sides and we'll have;} \\ 9x^2-30x+25+125=-125+125 \\ 9x^2-30x+150=0 \end{gathered}$

We shall now solve the resulting quadratic equation using the quadratic formula as follows;

$\begin{gathered} x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ \text{Where;} \\ a=9,b=-30,c=150 \\ x=\frac{-(-30)\pm\sqrt[]{(-30)^2-4(9)(150)}}{2(9)} \\ x=\frac{30\pm\sqrt[]{900-5400}}{18} \\ x=\frac{30\pm\sqrt[]{-4500}}{18} \\ x=\frac{30\pm\sqrt[]{-900\times5}}{18} \\ x=\frac{30\pm\sqrt[]{-900}\times\sqrt[]{5}}{18} \\ x=\frac{30\pm30i\sqrt[]{5}}{18} \\ \text{Therefore;} \\ x=\frac{30+30i\sqrt[]{5}}{18},x=\frac{30-30i\sqrt[]{5}}{18} \\ \text{Divide all through by 6, and we'll have;} \\ x=\frac{5+5i\sqrt[]{5}}{3},x=\frac{5-5i\sqrt[]{5}}{3} \end{gathered}$

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