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3 years ago

Analyze the pre-image ABCD. What are the vertices of the final image if T–1, –2 ◦ ry = x is applied to figure ABCD?

Mathematics

2 answers:

zysi [14]3 years ago

8 0

Answer:

A''

(3,0)

B''

(3, 2)

C''

(1,1)

D''

(1, -1)

just making sure nobody puts the wrong answer!

mariarad [96]3 years ago

6 0

Answers:

A''(3, 0); B''(3, 2); C''(1, 1); D''(1, -1)

Explanation:

We perform the reflection across y=x first. This reflection switches the x- and y-coordinates; this maps:

A(2, 4)→A'(4, 2)

B(4, 4)→B'(4, 4)

C(3, 2)→C'(2, 3)

D(1, 2)→D'(2, 1)

Next we perform the translation. This translation shifts the figure 1 unit left and 2 units down, by subtracting 1 from the x-coordinate and 2 from the y-coordinate. This maps:

A'(4, 2)→A''(3, 0)

B'(4, 4)→B''(3, 2)

C'(2, 3)→C''(1, 1)

D'(2, 1)→D''(1, -1)

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3(5b-1)=5 solve for b 4(3y-1)=20 solve for y

Gnom [1K]

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Get rid of the brackets
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7 0

3 years ago

Engineers must consider the breadths of male heads when designing helmets. The company researchers have determined that the popu

tia_tia [17]

Answer:

The minimum head breadth that will fit the clientele is 4.4 inches.

The maximum head breadth that will fit the clientele is 7.8 inches.

Step-by-step explanation:

Let X = head breadths of men that is considered for the helmets.

The random variable X is normally distributed with mean, μ = 6.1 and standard deviation, σ = 1.

To compute the probability of a normal distribution we first need to convert the raw scores to z-scores using the formula:

$z=\frac{x-\mu}{\sigma}$

It is provided that the helmets will be designed to fit all men except those with head breadths that are in the smallest 4.3% or largest 4.3%.

Compute the minimum head breadth that will fit the clientele as follows:

P (X < x) = 0.043

⇒ P (Z < z) = 0.043

The value of z for this probability is:

z = -1.717

*Use a z-table.

Compute the value of x as follows:

$z=\frac{x-\mu}{\sigma}\\-1.717=\frac{x-6.1}{1}\\x=6.1-(1.717\times 1)\\x=4.383\\x\approx4.4$

Thus, the minimum head breadth that will fit the clientele is 4.4 inches.

Compute the maximum head breadth that will fit the clientele as follows:

P (X > x) = 0.043

⇒ P (Z > z) = 0.043

⇒ P (Z < z) = 1 - 0.043

⇒ P (Z < z) = 0.957

The value of z for this probability is:

z = 1.717

*Use a z-table.

Compute the value of x as follows:

$z=\frac{x-\mu}{\sigma}\\1.717=\frac{x-6.1}{1}\\x=6.1+(1.717\times 1)\\x=7.817\\x\approx7.8$

Thus, the maximum head breadth that will fit the clientele is 7.8 inches.

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3 years ago

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Verizon [17]

Answer:

$\leq$ or $\geq$

Step-by-step explanation:

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3 years ago

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AlladinOne [14]

Step-by-step explanation:

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3 years ago

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larisa86 [58]

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Decimal Form:

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