Answer:
<em>B)</em><em> 8.9 lbs
</em>
<em>C)</em><em> 9.5 lbs
</em>
<em>D)</em><em> 9.8 lbs
</em>
<em>E)</em><em> 10.4 lbs</em>
Step-by-step explanation:
From the graph, 9.5 is the mean of the sample and 0.5 is the standard deviation of the sample.
As we have to find the weights that lie within the 2 standard deviations of the mean i.e


Among the given weights only 8.9 lbs, 9.5 lbs, 9.8 lbs, 10.4 lbs will lie within 2 standard deviations of the mean.
Answer:
0.0064
0.00032
Step-by-step explanation:
Given the details:
P(X > 3), n = 5, p = 0.2
The binomial distribution is related using the formula:
P(x = x) = nCx * p^x * q^(n-x)
q = 1 - p = 1 - 0.2 = 0.8
P(X > 3) = p(x = 4) + p(x = 5)
P(x = 4) = 5C4 * 0.2^4 * 0.8^1 = 5 * 0.2^4 * 0.8^1 = 0.0064
P(x = 5) = 5C5 * 0.2^5 * 0.8^0 = 1 * 0.2^5 * 0.8^0 = 0.00032
Answer:
The answer is D. Green; The experimental probability is 22.7%, and the theoretical probability is 15%.