Answer:
4
Step-by-step explanation:
Given algebraic expression: 6x^3y+7x^2+5x+46x3y+7x2+5x+4
We know that the constants are the terms in the algebraic expression that contain only numbers.
In the given expression only last term has only numerical value and no variable, rest of them have variable x.
Therefore, the constant term in the given algebraic expression 6x^3y+7x^2+5x+46x3y+7x2+5x+4 is
Answer:
honestly I THINK it's the first one
A quadratic equation has the general form
of: <span>
y=ax² + bx + c
It can be converted to the vertex form in order
to determine the vertex of the parabola. It has the standard form of:
y = a(x+h)² - k
This can be done by completing a square. The steps are as follows:
</span><span>y = 3x2 + 9x – 18
</span>y = 3(x2 <span>+ 3x) – 18
</span>y + 27/4= 3(x2 <span>+ 3x+ 9/4) – 18
</span>y = 3(x2 + 3/2)^2 – 99<span>/4
</span>
Therefore, the first step is to group terms with the variable x and factoring out the coefficient of x^2.
The question supplied is incomplete. The complete question is shown below:
The Gross national product (GNP) is the value of all the goods and services produced in an economy, plus the value of goods and services imported, less the goods and services exported. During the period of 1994-2004, the GNP of Canada grew about 4.8% per year, measured in 2003 dollars. In 1994, the GNP was $5.9 billion. Assuming this rate continues, in what year with the GNP reach $10 billion?
Answer:
2006
Step-by-step explanation:
Every year, the new GNP will become (100 + 4.8)% of that of the previous year. That is 104.8%, and equivalent of 1.048.
Let P(y) be the GNP after a period of y years.
After y years, the equation for calculating A(y) becomes
A(y)=5.9*(1.048)^y
Since A(y) = 10
10=5.9*(1.048)^y
10/5.9 =(1.048)^y
1.695=(1.048)^y
ln(1.695) = ln(1.048)^y
ln(1.695) = y ln1.048
y=ln1.695/ln1.048
y=11.26 years
1994 + 12 = 2006
Canada’s GNP will reach $10 billion in the year 2006
