861/4? Put a picture so I can answer
Remember that f(a) is the same thing as y just about. So the y value is -2. That's the flat part of the graph about.
You need an x value that is along the flat part of the graph.
The flat part goes from x = - 1 to x = 0
You need a value between 0 and - 1. The only value there that does that is B.
I don't know why the answer was given to you as A. It is not correct. Sometimes questions are like that. There's just an error in them. Appeal it with your teacher.
B <<<<<< answer.
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Step-by-step explanation:</h2>
If the graph of any function is an unbroken curve, then the function is continuous. Let's study the function at the the point [/tex]x=5[/tex]:
At this point the function has the following value:
, so the function in fact exists here, but let's find the limit here using:
So:
By factoring out this function we have:
Since then the function is continuous here.
Let's come back to our function:
If we factor out this function we get:
Notice that at x = 9 the denominator becomes 0 implying that at this x-value there is a vertical asymptote. The graph of this function is shown below and you can see that at x = 9 the function is not continous
Therefore, the answer is:
b. continous at every point exept
Answer:
Im so sorry bro.
Step-by-step explanation: