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fomenos
2 years ago
9

Where are the asymptotes for the following function located? f (x) = StartFraction 7 Over x squared minus 2 x minus 24 EndFracti

on.
Mathematics
1 answer:
Aleonysh [2.5K]2 years ago
3 0

The the asymptotes are at x = -4 and 6.

Now we have given

f(x)=\frac{7}{x^2-2x-24}

f(x) = ∞, is not defined for x²- 2x - 24 = 0.

.What is the regular hyperbola?

A rectangular parabola is a hyperbola having three transverse axes and the conjugate axis of equal length. The arcs of a rectangular hyperbola are the same as the arc of the circle. The general equation of the rectangular hyperbola is x² + y² = a²

Given  function is a,

f(x)=\frac{7}{x^2-2x-24}

To find the asymptotes of a hyperbola.

f(x) = ∞, is not defined when the denominator is 0

x^{2} - 2x - 24 = 0\\x^{2}  - (6-4) x - 24 = 0x^{2}  -6x + 4x -24 = 0( x - 6 ) ( x + 4 ) = 0

As the f(x) is not defined at -4 and 6.

Therefore,

The the asymptotes are at x = -4 and 6.

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I am attaching the full question...

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Answer:

x=4/3

Step-by-step explanation:

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Step-by-step explanation:

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Answer:

<em>x = -2,  y = -1</em>

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