Question

If h(x) = 5 x and k (x) = startfraction 1 over x endfraction, which expression is equivalent to (k circle h) (x)? startfraction (5 x) over x endfraction startfraction 1 over (5 x) endfraction 5 (startfraction 1 over x endfraction) 5 (5 x)

Answer 1

The composition of the two given functions is:

(k°h)(x) = 1/5x

How to get the composition of the functions?

Here we have the functions h(x) = 5x and k(x) = 1/x.

We want to get (k°h)(x), which is equal to:

k(h(x))

Then we have:

k(h(x)) = 1/h(x)

Replacing h(x) we get:

k(h(x)) = 1/h(x) = 1/(5x)

So the composition is just one over 5x.

If you want to learn more about compositions:

brainly.com/question/10687170

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