Question

Separate 79 into two parts such that 4 times the smaller exceeds the larger by 6.

Answer 1

39 is separated into two parts 9 and 30

Step-by-step explanation:

The given is:

Separate 39 into two parts

4 times the smaller part exceeds the larger part by 6

Assume that the smaller part is x and the larger part is y

∵ 39 is separate into two parts x and y

∴ x + y = 39 ⇒ (1)

∵ x is the smaller part

∵ y is the larger part

∵ 4 times the smaller part exceeds the larger part by 6

- Multiply x by 4 and subtract y from it to get 6

∴ 4x - y = 6 ⇒ (2)

Now we have a system of equations to solve it

Add equations (1) and (2) to eliminate y

∵ (x + 4x) + (y - y) = (39 + 6)

∴ 5x = 45

- Divide both sides by 5

∴ x = 9

Substitute the value of x in equation (1) to find y

∴ 9 + y = 39

- Subtract 9 from both sides

∴ y = 30

∴ The smaller part is 9 and the larger part is 30

39 is separated into two parts 9 and 30

Learn more:

You can learn more about the system of equations in brainly.com/question/6075514

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