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zavuch27 [327]
3 years ago
7

Which sentence is incorrect?

Mathematics
2 answers:
Olin [163]3 years ago
8 0
C is the incorrect sentence.
Anna [14]3 years ago
3 0
Both C and D are incorrect.

-2.5 is greater than -3 (-2.5 > -3)

-2/5 = -0.4, not 0.4
You might be interested in
Given p(x)= 3x+1 and r(x)= 2x^2+5 which of the following represents the composition p(r(x)) ?
Temka [501]

Step-by-step explanation:

substitute the values

px=3x+1

=(3x+1)/x

=3x/x +1/x

=3+1/x

rx=2x²+5

p(r(x)) =(3+1/x(2x²+5))

=6x²+15+2x²/x+5/x

=3(2x²+5)+1/x(2x²+5)

=(2x²+5)(3+1/x)

6 0
2 years ago
Select the number that is the same as 29%.
vlada-n [284]

1/29 or 29/100 would be your awnser


5 0
3 years ago
An electronics company makes communication devices for military contracts. The company just completed two contracts. The navy co
adelina 88 [10]

Answer:

Workers of army contract were more productive.

Step-by-step explanation:

To determine on which contract the workers were more productive compute the work done per hour by the workers for both contracts.

  • <u>Navy Contract</u>:

Number of devices = 2,300

Number of workers = 25

Number of weeks = 2 weeks

Number of hours per week = 40

The number of hours it took 25 workers to produce 2300 devices is =

=25\times2\times40\\=2000\ hours

Then number of devices produced in 1 hour is = \frac{2300}{2000}= 1.15\ devices\ per\ hour

  • <u>Army Contract</u>:

Number of devices = 5,500

Number of workers = 35

Number of weeks = 3 weeks

Number of hours per week = 40

The number of hours it took 35 workers to produce 5500 devices is ==35\times3\times40\\=4200\ hours

Then number of devices produced in 1 hour is = \frac{5500}{4200}= 1.31\ devices\ per\ hour

The workers for the army contract are more productive since they produce 1.31 devices per hour whereas the workers for navy contract produces 1.15 devices per hour.

4 0
2 years ago
Please help :))
fredd [130]

Answer:

0.15

Step-by-step explanation:

Fp: frequency that the pitcher will throw exactly 4 pitches to a batter=15

Fa: frequency that the pitcher will throw any pitches to a batter=15+20+40+15+10=100

P=Fp/Fa=15/100=0.15

7 0
2 years ago
Mateo teaches a continuing education class at the library on tuesday nights. he estimates that 75% of his students are satisfied
vredina [299]

The computed value must closely match the real value for a model to be considered valid. If the percentage of pleased or very satisfied students remains close to 75% after Mateo surveys additional students, Mateo's model is still viable. The model is faulty if the opposite is true.

<h3>How will mateo know whether his model is valid or not?</h3>

In general, a valid model is one whose estimated value is close to the real value. This kind of model is considered to be accurate. It must be somewhat near to the real value if it doesn't resemble the real value.

If the findings of the survey are sufficiently similar to one another, then the model may be considered valid.

P1 equals 75%, which is the real assessment of the number of happy pupils

P2 is 70 percent; this represents the second assessment of happy pupils

In conclusion,  The estimated value of a model has to be somewhat close to the real value for the model to be considered valid. If the number of students who are either pleased or extremely satisfied remains close to 75 percent following Mateo's survey of more students, then Mateo's model is likely accurate. In any other scenario, the model cannot be trusted.

Read more about probability

brainly.com/question/795909

#SPJ1

7 0
1 year ago
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