Answer: The required probability is 0.1923.
Step-by-step explanation:
Since we have given that
Probability that it's a good dog = 0.4
Probability that it's a bad dog = 1-0.4 = 0.6
Probability that the dog smokes given that its a bad dog = 0.7
Probability that it smokes given that its a good dog = 0.25
According to question, probability of smoking pipe would be
P(good).P(Smoking pipe|good)+P(bad).P(smoking pipe|bad)

So, Probability of getting a good dog given that it is smoking pipe is given by

Hence, the required probability is 0.1923.
Answer: 44! Hope this helps :D
Step-by-step explanation:
Hi!
This is a fun one, as it delves into basic trigonometry.
We're going to use the Pythagorean theorem here, which says that for right triangles where "c" is the hypotenuse,
a² + b² = c²
We have to split this large triangle into two parts, both of which are right triangles. (This is why they drew a line in the middle to tell you that the larger triangle is composed of two right triangles.)
Let's do the one on the right first.
We know that the length of the hypotenuse is 10, and that the length of one of the legs is 6.5. If we plug this into our equation, we'll get the length of the other leg. I'm choosing "b" to be 6.5, but it really doesn't matter if you pick "a" or "b", so long as you reserve "c" for the hypotenuse (longest side).
a² + 6.5² = 10²
a² + 42.25 = 100
a² = 57.75
√a² = √57.75
a ≈ 7.6
Therefore, the length of DC is about 7.6.
Find the length of AD using the same method (7.5 is the hypotenuse "c", and 6.5 is one of the legs "a" or "b"). Then, once you have AD, add the lengths of AD and DC to get AC.
Have a great one!
Answer:

Step-by-step explanation:

Answer:
the rate of the first cyclist: 28km/h
the rate of the 2nd cyclist 28+4= 32km/h
Step-by-step explanation:
x= the rate of the first cyclist
x+4= the rate of the 2nd cyclist
after 4 hours: + the first cyclist travels 4x (km)
+ the 2nd cyclist travels 4(x+4) (km)
because the two cyclists are 240 km apart after 4 hours
=> 4x + 4(x+4) = 240 => x= 28
i hope it's useful forr u =)))