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Ghella [55]
3 years ago
12

HELPPPPPPPPPPPP With this question ( taking quiz)

Mathematics
2 answers:
Serggg [28]3 years ago
7 0

You are correct, it is a water bottle

creativ13 [48]3 years ago
3 0

Answer:

swimming pool

Step-by-step explanation:

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A multiple-choice examination has 20 questions, each with five possible answers, only one of which is correct. Suppose that one
kari74 [83]

Answer:

The probability that the student answers at least seventeen questions correctly is 8.03\times 10^{-10}.

Step-by-step explanation:

Let the random variable <em>X</em> represent the number of correctly answered questions.

It is provided all the questions have five options with only one correct option.

Then the probability of selecting the correct option is,

P(X)=p=\frac{1}{5}=0.20

There are <em>n</em> = 20 question in the exam.

It is also provided that a student taking the examination answers each of the questions with an independent random guess.

Then the random variable can be modeled by the Binomial distribution with parameters <em>n</em> = 20 and <em>p</em> = 0.20.

The probability mass function of <em>X</em> is:

P(X=x)={20\choose x}\ 0.20^{x}\ (1-0.20)^{20-x};\ x =0,1,2,3...

Compute the probability that the student answers at least seventeen questions correctly as follows:

P(X\geq 17)=P (X=17)+P (X=18)+P (X=19)+P (X=20)

=\sum\limits^{20}_{x=17}{{20\choose x}\ 0.20^{x}\ (1-0.20)^{20-x}}\\\\=0.00000000077+0.000000000032+0.00000000000084+0.000000000000042\\\\=0.000000000802882\\\\=8.03\times10^{-10}

Thus, the probability that the student answers at least seventeen questions correctly is 8.03\times 10^{-10}.

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What is the product?
SSSSS [86.1K]
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Use the properties of exponents to determine the value of a for the equation:
sleet_krkn [62]

<em>Answer:</em>

<em>    You need to do 1x to the 3rd power and then do the x with the division sign on a calculator. After those two steps divide the answer for 1x to the 3rd power by the x with the division sign. Then the answer that you get will most likely be the answer for a. </em>

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