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shepuryov [24]
2 years ago
14

Two men walk at rates of 6 mph and 10 mph, respectively. Simultaneously, they started from the same place walking waking in oppo

site directions. In how many hours will they be 200 miles apart?
Mathematics
1 answer:
VladimirAG [237]2 years ago
6 0

Answer:

12.5 hours :)

Step-by-step explanation:

Let after t hours , the two men are 200 miles apart

So the distance traveled by fthe irst man is 6 miles

And the distance traveled by the second man is 10 miles

So the equation is 6t+10t=200

Therefore after 12.5 hours, they are 200 miles apart.

P.S. Please give me brainliest!

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The answer to the question above is "a. This transaction will decrease Korey’s gross monthly profit by $625" based on Korey's financial situation above. Korey has purchased the $625 assortment of comic however he will not receive his new additional comics until last month. This transaction will increase his cost of good sold and decrease his gross profit.
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4 years ago
Read 2 more answers
Help this question is due in like 15 minutes :p
fomenos

Answer:

A= 150°

B=30°

C=150°

Step-by-step explanation:

Since a line is 180°, you can write an equation for C. C+30°=180° , from here use algebra to find C. The value of C will be 150°. When the value of C is 150° , since they're supplementary angles, the value of A will also be 150°.

Important thing to note:

The value of all these angles combined together is 360°.

5 0
3 years ago
Find , , and if and terminates in quadrant .
ioda

sin2x =12/13

cos2x = 5/13

tan2x = 12/5

STEP - BY - STEP EXPLANATION

What to find?

• sin2x

,

• cos2x

,

• tan2x

Given:

tanx = 2/3 = opposite / adjacent

We need to first make a sketch of the given problem.

Let h be the hypotenuse.

We need to find sinx and cos x, but to find sinx and cosx, first determine the value of h.

Using the Pythagoras theorem;

hypotenuse² = opposite² + adjacent²

h² = 2² + 3²

h² = 4 + 9

h² =13

Take the square root of both-side of the equation.

h =√13

This implies that hypotenuse = √13

We can now proceed to find the values of ainx and cosx.

Using the trigonometric ratio;

\sin x=\frac{opposite}{\text{hypotenuse}}=\frac{2}{\sqrt[]{13}}\cos x=\frac{adjacent}{\text{hypotenuse}}=\frac{3}{\sqrt[]{13}}

And we know that tanx =2/3

From the trigonometric identity;

sin 2x = 2sinxcosx

Substitute the value of sinx , cosx and then simplify.

\sin 2x=2(\frac{2}{\sqrt[]{13}})(\frac{3}{\sqrt[]{13}})=\frac{12}{13}

Hence, sin2x = 12/13

cos2x = cos²x - sin²x

Substitute the value of cosx, sinx and simplify.

\begin{gathered} \cos 2x=(\frac{3}{\sqrt[]{13}})^2-(\frac{2}{\sqrt[]{13}})^2 \\  \\ =\frac{9}{13}-\frac{4}{13} \\ =\frac{5}{13} \end{gathered}

Hence, cos2x = 5/13

tan2x = 2tanx / 1- tan²x

\tan 2x=\frac{2\tan x}{1-\tan ^2x}=\frac{2(\frac{2}{3})}{1-(\frac{2}{3})^2}=\frac{\frac{4}{3}}{1-\frac{4}{9}}=\frac{\frac{4}{3}}{\frac{9-4}{9}}=\frac{\frac{4}{3}}{\frac{5}{9}}=\frac{4}{3}\times\frac{9}{5}=\frac{4}{1}\times\frac{3}{5}=\frac{12}{5}

OR

\tan 2x=\frac{\sin 2x}{\cos 2x}=\frac{\frac{12}{13}}{\frac{5}{13}}=\frac{12}{5}

Hence, tan2x = 12/5

Therefore,

sin2x =12/13

cos2x = 5/13

tan2x = 12/5

3 0
1 year ago
(05.02 MC) A system of equations is shown below: 4x = −3y + 17 3x − 4y = −6 What is the solution to this system of equations? (−
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4x+3y=17
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elimination

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9x-12y=-18
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sub back

3x-4y=-6
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(x,y)
(2,3)
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The equation of a circle with centre (a,b) and radius r is:
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which is c.

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3 years ago
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