Answer:
Tnbp = 731.44 K
Explanation:
Trouton's law:
∴ Tnbp: temperature at normal boiling point
∴ ΔH°vap = 54.2 KJ/mol
∴ ΔS°vap = (74.1 J/mol.K)×(KJ/1000 J) = 0.0741 KJ/mol.K
⇒ Tnbp = ΔH°vap / ΔS°vap
⇒ Tnbp = (54.2 KJ/mol) / (0.0741 KJ/mol.K)
⇒ Tnbp = 731.44 K
Classification ,
correct me if i’m wrong
Answer:
chemistry
Explanation:
In standardizing a potassium .hydroxide solution, a student finds that 32.60mL of the base solution is needed to titrate 0.5045 grams of KHP to a phenolphthalein endpoint. In another titration, 26.63mL of this same base solution is needed to titrate 0.2003grams of an unknown solid monoprotic acid.
<h2>pls, branliest! :)</h2>
Answer:
D
Explanation:
the products are always what you end with so it doesn't matter what happens during the reaction.