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3 years ago

Which substance is oxidized and which is reduced in this reaction?

Chemistry

1 answer:

Eddi Din [679]3 years ago

6 0

Answer:

A) HBr oxidized; HCl reduced

Explanation:

Chemical equation:

Cl₂ + 2HBr → 2HCl + Br₂

The given reaction is redox reaction because oxidation reduction take place.

Cl₂ is reduced from oxidation state 0 to -1 while HBr oxidized from -1 to 0.

Chlorine is oxidizing agent while HBr is reducing agent.

Oxidation:

Oxidation involve the removal of electrons and oxidation state of atom of an element is increased.

Reduction:

Reduction involve the gain of electron and oxidation number is decreased.

Oxidizing agents:

Oxidizing agents oxidize the other elements and itself gets reduced.

Reducing agents:

Reducing agents reduced the other element are it self gets oxidized

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3 years ago

One reaction involved in the conversion of iron ore to the metal is FeO(s) + CO(g) → Fe(s) + CO2(g) Use Hess’s Law to calculate

Ugo [173]

Answer:

$\delta H_{rxn} = -66.0 \ kJ/mole$

Explanation:

Given that:

$3FeO_3_{(s)}+CO_{(g)} \to 2Fe_3O_4_{(s)} +CO_{2(g)} \ \ \delta H = -47.0 \ kJ/mole -- equation (1) \\ \\ \\ Fe_2O_3_{(s)} +3CO_{(g)} \to 2FE_{(s)} + 3CO_{2(g)} \ \ \delta H = -25.0 \ kJ/mole -- equation (2) \\ \\ \\ Fe_3O_4_{(s)} + CO_{(g)} \to 3FeO_{(s)} + CO_{2(g)} \ \delta H = 19.0 \ kJ/mole -- equation (3)$

From equation (3) , multiplying (-1) with equation (3) and interchanging reactant with the product side; we have:

$3FeO_{(s)} + CO_{2(g)} \to Fe_3O_4_{(s)} + CO_{(g)} \ \delta H = -19.0 \ kJ/mole -- equation (4)$

Multiplying (2) with equation (4) ; we have:

$6FeO_{(s)} + 2CO_{2(g)} \to 2Fe_3O_4_{(s)} + 2CO_{(g)} \ \delta H = -38.0 \ kJ/mole -- equation (5)$

From equation (1) ; multiplying (-1) with equation (1); we have:

$2Fe_3O_4_{(s)} +CO_{2(g)} \to 3FeO_3_{(s)}+CO_{(g)} \ \ \delta H = 47.0 \ kJ/mole -- equation (6)$

From equation (2); multiplying (3) with equation (2); we have:

$3 Fe_2O_3_{(s)} +9CO_{(g)} \to 6FE_{(s)} + 9CO_{2(g)} \ \ \delta H = -75.0 \ kJ/mole -- equation (7)$

Now; Adding up equation (5), (6) & (7) ; we get:

$6FeO_{(s)} + 2CO_{2(g)} \to 2Fe_3O_4_{(s)} + 2CO_{(g)} \ \delta H = -38.0 \ kJ/mole -- equation (5)$

$2Fe_3O_4_{(s)} +CO_{2(g)} \to 3FeO_3_{(s)}+CO_{(g)} \ \ \delta H = 47.0 \ kJ/mole -- equation (6)$

$3 Fe_2O_3_{(s)} +9CO_{(g)} \to 6FE_{(s)} + 9CO_{2(g)} \ \ \delta H = -75.0 \ kJ/mole -- equation (7)$

$FeO \ \ \ + \ \ \ CO \ \ \to \ \ \ \ Fe_{(s)} + \ \ CO_{2(g)} \ \ \ \delta H = - 66.0 \ kJ/mole$

$\delta H_{rxn} = \delta H_1 + \delta H_2 + \delta H_3$ (According to Hess Law)

$\delta H_{rxn} = (-38.0 + 47.0 + (-75.0)) \ kJ/mole$

$\delta H_{rxn} = -66.0 \ kJ/mole$

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3 years ago

Fulgurites are the products of the melting that occurs when lightning strikes the earth. Microscopic examination of a sand fulgu

BlackZzzverrR [31]

Answer:

Fe₃Si₇

Explanation:

In order to determine the empirical formula, we have to follow a series of steps.

Step 1: Determine the percent composition

Fe: 46.01%

Si: 53.99%

Step 2: Divide each percentage by the atomic mass of the element

Fe: 46.01/55.85 = 0.8238

Si: 53.99/28.09 = 1.922

Step 3: Divide all the numbers by the smallest one

Fe: 0.8238/0.8238 = 1

Si: 1.922/0.8238 = 2.33

Step 4: Multiply by numbers that make the coefficients whole.

Fe: 1 × 3 = 3

Si: 2.33 × 3 = 7

The empirical formula is Fe₃Si₇.

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a block of wood has a density of 0.95 g/cm3. will it float or sink when placed on a liquid with a density of 0.88 g/mL? explain

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NikAS [45]

Answer:

Structures are given below.

Explanation:

Treatment of 2-bromo-2-methylbutane with KOH in ethanol will give elimination of HBr through E2 mechanism.
H atoms adjacent to Br will be eliminated.
2-bromo-2-methylbutane has two possible adjacent H atoms that can be eliminated giving mixture of products.
Product of this elimination reaction is alkene. Here saytzeff fule is followed during elimination. So most substituted alkene will be major product.
Structure of alkenes are given below.

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3 years ago