Answer:
ONES Period
Step-by-step explanation:
Answer:
Option A)
congruent with 
Step-by-step explanation:
There is only information about two sides in each triangle, so there is still the need of a third piece of info which can come from an angle like
congruent with
, which are angles opposite to one of the given sides on each triangle.
C) (-3, 1) is the answer
The maximum value is the highest point.
As with any "solve for ..." problem, you start by looking at the operations performed on the variable of interest. Here, when you evaluate this expression according to the order of operations, you
- add b1
- multiply by (h/2)
When you want to solve for b2, you undo these operations in reverse order. To undo multiplication by a fraction, you multiply by the inverse (reciprocal) of the fraction. To undo addition, you add the opposite.
Whatever you do must be done to both sides of the equation.
Here we go ...
... (2/h)A = b1 + b2 . . . . . we undid the multiply by h/2, by multiplying by 2/h
... (2/h)A - b1 = b2 . . . . . we undid the addition of b1 by adding the opposite of b1
Then your solution is
... b2 = 2A/h - b1
If you want to, you can combine these terms over a single denominator to get
... b2 = (2A -h·b1)/h
A is 32 because
2a=64
a=64/2