Answer:
181.8 yd
Step-by-step explanation:
The law of cosines is good for this. It tells you for triangle sides 'a' and 'b' and included angle C, the length of 'c' is given by ...
c^2 = a^2 +b^2 -2ab·cos(C)
For the given geometry, this is ...
c^2 = 400^2 +240^2 -2(400)(240)cos(16°) ≈ 33,037.75
c ≈ √33037.75 ≈ 181.8 . . . yards
Marsha's ball is about 181.8 yards from the hole.
<h3>
Answer: approximately 0.19 meters long</h3>
The more accurate value is 0.18982439916059 but this value isn't exact
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Explanation:
The volume of this rectangular block is 0.24*0.19*0.15 = 0.00684 cubic meters.
If we had a cube of this volume, then it has some side length x such that x^3 = 0.00684
Apply the cube root to both sides. This is the same as raising both sides to the 1/3 power
![x^3 = 0.00684\\\\x = \sqrt[3]{0.00684}\\\\x = (0.00684)^{1/3}\\\\x \approx 0.18982439916059\\\\x \approx 0.19\\\\](https://tex.z-dn.net/?f=x%5E3%20%3D%200.00684%5C%5C%5C%5Cx%20%3D%20%5Csqrt%5B3%5D%7B0.00684%7D%5C%5C%5C%5Cx%20%3D%20%280.00684%29%5E%7B1%2F3%7D%5C%5C%5C%5Cx%20%5Capprox%200.18982439916059%5C%5C%5C%5Cx%20%5Capprox%200.19%5C%5C%5C%5C)
The side length of the cube is approximately 0.19 meters long
Answer:
It will be $40.00
Step-by-step explanation:
hope this helps
(m.v^2)/ 2 = 25000
<=> 500.v^2 = 50000
<=> v^2 = 100
<=> v = 10 m/s