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Andrei [34K]
3 years ago
6

8.752 divided by 0.12 Pls show steps

Mathematics
2 answers:
katrin [286]3 years ago
6 0

Answer:

72.933333

Step-by-step explanation:

Snowcat [4.5K]3 years ago
4 0
8.752 divided by 0.12 is 72.93.
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What is the value of X if 5^x^+^2=5^9?<br> X=-11<br> X=-7<br> X=7<br> X=11
notsponge [240]

Answer:

\large\boxed{x=7}

Step-by-step explanation:

5^{x+2}=5^9\iff x+2=9\qquad\text{subtract 2 from both sides}\\\\x+2-2=9-2\\\\x=7

5 0
4 years ago
Find the equation of a line that is parallel to y = x + 1 and passes through the point (3,-4).
White raven [17]

Given:

The equation of a line is:

y=x+1

A line is parallel to the given line and passes through the point (3,-4).

To find:

The equation of the line in the slope intercept form.

Solution:

The slope intercept form of a line is:

y=mx+b             ...(i)

Where, m is the slope and b is the y-intercept of the line.

We have,

y=x+1                ...(ii)

On comparing (i) and (ii), we get

m=1

Slope of the given line is 1.

We know that the slopes of parallel lines are equal. So, the slope of the required line is 1.

The required line passes through the point (3,-4) with slope 1. So, the equation of the required line is:

y-y_1=m(x-x_1)

y-(-4)=1(x-3)

y+4=x-3

Subtracting 4 from both sides, we get

y=x-3-4

y=x-7

Therefore, the equation of the required line is y=x-7.

4 0
3 years ago
A thermometer is taken from an inside room to the outside, where the air temperature is 20° f. after 1 minute the thermometer re
fomenos

The change in the temperature is proportional to the difference in temperatures. Let's call the initial temperature of the room and the thermometer E_0 and the current temperature E(t) where t is the elapsed time in minutes.  The outside temperature is 20 F.

Newton's Law of Cooling:

E(t) - 20 = (E_0 - 20) e^{- k t}

We're given E(1)=70 \textrm{ and } E(5)=45

70-20 = (E_0 - 20) e^{-k}

45-20 =(E_0 - 20) e^{-5k}

Dividing,

\dfrac{50}{25}=e^{4k}

k = \dfrac 1 4 \ln 2

Now,

E(t) - 20 = (E_0 - 20) e^{- k t}

E_0 = 20 + (E(t) - 20)e^{k t}

E_0 = 20 + (E(1) - 20)e^{k}

E_0 = 20 + (70 - 20)e^{\ln 2/4}

E_0 = 20 + 50 \cdot 2^{1/4} \approx 79.46 \textrm{ degrees F}


3 0
4 years ago
Graph y = -2x + 5 and y = -1/2x - 3
Umnica [9.8K]
Take a look at the document I had attached to my answer for what the graph looks like:

8 0
3 years ago
Help- plato ) <br>The second- degree term of the expression x^ + 12 X
KatRina [158]

Answer:

Correct Answer is 1 Only 5 x 2 5x2 is the second-degree term. Hence, the correct option is (1)

note :

hope i helped

3 0
3 years ago
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