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kramer
1 year ago
9

3(2x + 5)= 4 (c-3) I know how to solve it but can someone explain it.

Mathematics
1 answer:
Nezavi [6.7K]1 year ago
5 0

Answer:

3x×2c+1

Step-by-step explanation:

6x+15 =4c-12

\frac{6x + 15}{4c - 12}  =  \frac{4c - 12}{4c - 12}

\frac{6x + 15}{4c - 12}

\frac{3x  + 5}{2c - 4}

3x + 5 \div 2c - 4

3x  \times 2c + 5 - 4

3x \times 2c + 1

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Answer:

The probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.

Step-by-step explanation:

Let the random variable <em>X</em> represent the time a child spends waiting at for the bus as a school bus stop.

The random variable <em>X</em> is exponentially distributed with mean 7 minutes.

Then the parameter of the distribution is,\lambda=\frac{1}{\mu}=\frac{1}{7}.

The probability density function of <em>X</em> is:

f_{X}(x)=\lambda\cdot e^{-\lambda x};\ x>0,\ \lambda>0

Compute the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning as follows:

P(6\leq X\leq 9)=\int\limits^{9}_{6} {\lambda\cdot e^{-\lambda x}} \, dx

                      =\int\limits^{9}_{6} {\frac{1}{7}\cdot e^{-\frac{1}{7} \cdot x}} \, dx \\\\=\frac{1}{7}\cdot \int\limits^{9}_{6} {e^{-\frac{1}{7} \cdot x}} \, dx \\\\=[-e^{-\frac{1}{7} \cdot x}]^{9}_{6}\\\\=e^{-\frac{1}{7} \cdot 6}-e^{-\frac{1}{7} \cdot 9}\\\\=0.424373-0.276453\\\\=0.14792\\\\\approx 0.148

Thus, the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.

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Step-by-step explanation:

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(3 - i) + (1 - 2i) =
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3 years ago
Which of the following does not describe 10x?
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I think it would be A.
hopefully this helped ᵔᴥᵔ
if it did dont forget to mark brainliest
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3 years ago
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