Given that, Nathan shares out 12 sweets, if he gives Yasmin 1 sweet for 3 sweets he buys, Nathan will get 9 sweets.
<h3>How many sweets does Nathan gets?</h3>
Given that, Nathan shares out 12 sweets, he gives Yasmin 1 sweet for 3 sweets he buys.
Let the sweet be represented by x
For each x sweet for Yasmin, Nathan gets 3x sweets
Hence
x + 3x = 12
We solve for x
4x = 12
x = 12/4
x = 3
Hence;
Yasmin gets x sweet = 3
Nathan gets 3x sweets = 3 × 3 = 9
Given that, Nathan shares out 12 sweets, if he gives Yasmin 1 sweet for 3 sweets he buys, Nathan will get 9 sweets.
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Answer:
The one in the right top hand corner. It shows one arrow pointing up and one to the right.
Step-by-step explanation:
I can't really explain it.
First list all the terms out.
e^ix = 1 + ix/1! + (ix)^2/2! + (ix)^3/3! ...
Then, we can expand them.
e^ix = 1 + ix/1! + i^2x^2/2! + i^3x^3/3!...
Then, we can use the rules of raising i to a power.
e^ix = 1 + ix - x^2/2! - ix^3/3!...
Then, we can sort all the real and imaginary terms.
e^ix = (1 - x^2/2!...) + i(x - x^3/3!...)
We can simplify this.
e^ix = cos x + i sin x
This is Euler's Formula.
What happens if we put in pi?
x = pi
e^i*pi = cos(pi) + i sin(pi)
cos(pi) = -1
i sin(pi) = 0
e^i*pi = -1 OR e^i*pi + 1 = 0
That is Euler's identity.
