Yep it is greater. Hope this helps
Answer:
Where's the question?
Step-by-step explanation:
Answer: A translation 5 units down followed by a 180-degree counterclockwise rotation about the origin .
Step-by-step explanation:
From the given figure, the coordinates of ΔABC are A(-3,4), B(-3,1), C(-2,1) and the coordinates of ΔA'B'C' are A'(3,1), B'(3,4), C'(2,4).
When, a translation of 5 units down is applied to ΔABC, the coordinates of the image will be
Then applying 180° counterclockwise rotation about the origin, the coordinates of the image will be :-
which are the coordinates of ΔA'B'C'.
Hence, the set of transformations is performed on triangle ABC to form triangle A’B’C’ is " A translation 5 units down followed by a 180-degree counterclockwise rotation about the origin ".
The value of the cosine ratio cos(L) is 5/13
<h3>How to determine the cosine ratio?</h3>
The complete question is added as an attachment
Start by calculating the hypotenuse (h) using
h^2 = 5^2 + 12^2
Evaluate the exponent
h^2 = 25 + 144
Evaluate the sum
h^2 = 169
Evaluate the exponent of both sides
h = 13
The cosine ratio is then calculated as:
cos(L) = KL/h
This gives
cos(L) =5/13
Hence, the value of the cosine ratio cos(L) is 5/13
Read more about right triangles at:
brainly.com/question/2437195
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Answer:
13x+12
Step-by-step explanation:
27x-14x=13
+12 because there is nothing else there
