B,the printer only receives signals from the computer and prints them.
It could be any thing of your chose
Explanation:
Case-sensitivity is inherently faster to parse (albeit only slightly) since it can compare character sequences directly without having to figure out which characters are equivalent to each other. It allows the implementer of a class/library to control how casing is used in the code.
Answer:
Answer is in the provided screenshot!
Explanation:
Steps required to solve this problem:
1 - define what characters are "vowels" by assigning them to an array.
2 - create a variable to record the amount of vowels there are in the string.
3 - convert the input string into a character array and iterate through each character
4 - for each of the character of the string we go through, check if it matches any of the vowels
5 - return true if the vowel count is greater than 1
Alternative methods using the Java Stream API have also been wrote, please respond if you require them.
Is this supposed to be a true or false question?