Question not well presented
Point S is on line segment RT . Given RS = 4x − 10, ST=2x−10, and RT=4x−4, determine the numerical length of RS
Answer:
The numerical length of RS is 22
Step-by-step explanation:
Given that
RS = 4x − 10
ST=2x−10
RT=4x−4
From the question above:
Point S lies on |RT|
So, RT = RS + ST
Substitute values for each in the above equation to solve for x
4x - 4 = 4x - 10 + 2x - 10 --- collect like terms
4x - 4 = 4x + 2x - 10 - 10
4x - 4 = 6x - 20--- collect like terms
6x - 4x = 20 - 4
2x = 16 --- divide through by 2
2x/2 = 16/2
x = 8
Since, RS = 4x − 10
RS = 4*8 - 10
RS = 32 - 10
RS = 22
Hence, the numerical length of RS is calculated as 22
Answer:
1. (n + 3)(5n + 8)
2. (x - 4)(7x - 4)
3. (k + 8)(7k + 1)
Step-by-step explanation:
1. We have to factorize 5n² + 23n + 24.
Now, 5n² + 23n + 24
= 5n² + 15n + 8n + 24
= 5n (n + 3) + 8 (n + 3)
=(n + 3)(5n + 8) (Answer)
2. We have to factorize 7x² - 32x + 16
Now, 7x² - 32x + 16
= 7x² - 28x - 4x + 16
= 7x (x - 4) - 4 (x - 4)
= (x - 4)(7x - 4) (Answer)
3. We have to factorize 7k² + 57k + 8
Now, 7k² + 57k + 8
= 7k² + 56k + k + 8
= 7k (k + 8) + 1 (k + 8)
= (k + 8)(7k + 1) (Answer)
Answer:
Is non-linear
Step-by-step explanation:
It is a quadratic function
