9514 1404 393
Answer:
B. 91
Step-by-step explanation:
14C12 = 14!/(12!(14-12)!) = 14·13/(2·1) = 7·13 = 91
Answer:
x = -11/5 and y = 24/5
Step-by-step explanation:
Use elimination.
First, we need to multiply so that at least one variable can cancel out.
We can multiply the top equation by 2.
So we get
4x + 6y = 20
Then, we can use elimination.
The x's cancel out.
So we get 5y = 24
Or y = 24/5
Then, we can plug in this y value back into the first equation to find x.
2x + 3(24/5) = 10
2x + 72/5 = 50/5
2x = -22/5
x = -11/5
So x = -11/5 and y = 24/5
Answer:
= 34.5
Step-by-step explanation:
The n th term of an arithmetic sequence is
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Given
= 121.5, then
a₁ + (69 × 1.5) = 121.5
a₁ + 103.5 = 121.5 ( subtract 103.5 from both sides )
a₁ = 18
Hence
= 18 + (11 × 1.5) = 18 + 16.5 = 34.5
Answer:
<u>The only x-intercept is x = 1</u>
Step-by-step explanation:
The equation is:

We can substitute y for r(x), to write in the notation:

To get y-intercept, we put x = 0
and
To get x-intercept, we put y =0
We want to find x-intercepts here, so we substitute 0 into y and solve for x. Shown below:

<u>The only x-intercept is x = 1</u>
Answer:
34
Step-by-step explanation:
We are here given a modulus expression and we need to find out the value when m = -5 and n = 3 .
<u>Modulus</u><u> </u><u>:</u><u>-</u> It always gives positive value . For example ,
<u>The </u><u>given</u><u> </u><u>modulus </u><u>expression</u><u> is</u><u> </u><u>:</u><u>-</u><u> </u>
As the number inside the modulus operator are already squared therefore they will always give positive value for real numbers . Here we can omit the modulus .
Plug in the given values ,
Solve 5² and 3² and add them ,

On adding ,
Therefore ,
<u>Hence</u><u> the</u><u> </u><u>required</u><u> answer</u><u> is</u><u> </u><u>34</u><u> </u><u>.</u>