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allsm [11]
2 years ago
8

At Webster Elementary School, of

Mathematics
1 answer:
Tcecarenko [31]2 years ago
8 0
Answer:
8/12 of fifth graders at Webster are enrolled in
art camp

Step-by-step explanation:
Question: At Webster Elementary School, 4/6 of the fifth graders are enrolled in summer camps. Of the students enrolled in summer camps, 8/12 are enrolled in an art camp. What fraction of the fifth graders at Webster are enrolled in art camp?

Given:
4/6 of the fifth graders are enrolled in summer camps.
8/12 are enrolled in an art camp.

fraction of the fifth graders enrolled in art camp:
find common denominator, 4/6 x 2/2 = 8/12
8/12 = 4/6 which means all went to art camp

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Solve this
ValentinkaMS [17]

\sqrt{33 +  \sqrt{4 +  \sqrt{50 \cos(60°) } } }

  • Now, we know cos(60°) = \frac {1}{2}. So put the value there.

\sqrt{33 +  \sqrt{4 +  \sqrt{50 \times  \frac{1}{2} } } }  \\  =  \sqrt{33 +  \sqrt{4 +  \sqrt{25} } }  \\  =  \sqrt{33 +  \sqrt{4 +  5 } }  \\  =  \sqrt{33 +  \sqrt{9} }  \\  =  \sqrt{33 + 3}  \\  =  \sqrt{36}  \\  = 6

Hence LHS = RHS [Proved]

Hope you could understand.

If you have any query, feel free to ask.

4 0
3 years ago
Which value from the set (3,8,9,14) makes the equation true?<br><br> 2n - 5 = 11
NeX [460]

Answer:

3

Step-by-step explanation:

Solve for n

3 0
3 years ago
Answer the above question ​
Svetach [21]

Answer:

Using Pyhagoras Theorem for the right-angled triangle ABO,

h² = 12² + 16² = 400.

∴ The length of the side of the rhombus is 20 cm.

★½×24×32 = 20×h

∴ h= 19.2 cm.

3 0
3 years ago
Read 2 more answers
Bob, Celia, Sam and Daniel gave money to buy their boss a retirement gift. Sam and Daniel each gave the same amount of money. Ce
cricket20 [7]

here's the equation: x+x+(x+12)+ 1/2(x+12) =81

combine like terms

(x+x+x+1/2x) + (12+6) = 81

simplify

7/2x +18=

subtract 18 from both sides.

7/2x=63

multiply by reciprocal (aka 2/7)

x=18

18+12=30 so celia gave 30.

Hope this helps!

8 0
3 years ago
A jazz concert brought in $134,000 on the sale of 8,500 tickets. If the tickets sold for $10 and $20 each, how many of each type
WINSTONCH [101]

Answer:

3600 $10 tickets

4900 $20 tickets

Step-by-step explanation:

We can use variables to represent the different types of tickets. Let "x" represent the amount of $10 tickets and "y" represent the amount of $20 tickets. Now we can set up a system of equations.

<h3>Setting up a System of Equations</h3>

We know that in total, 8500 tickets were sold. Therefore...

x+y=8500

Or in other words, "the amount of $10 tickets plus the amount of $20 tickets is equivalent to 8500 tickets in total".

We also know that $134,000 was made. Therefore...

10x+20y=134000

Or in other words, "10 times the amount of $10 tickets plus the 20 times the amount of $20 tickets is equivalent to 134000". Notice that since each ticket costs $10/$20, we have to multiply each variable by that value. We can now solve this system of equations.

<h3>Solving the System of Equations</h3>

x+y=8500\\10x+20x=134000

We can solve this system of equations using the elimination method. First, make either the x or y value equivalent in both equations. To do this, we can multiply a whole equation by a certain value.

Multiply the first equation by 10:

10x+10y=85000\\10x+20y=134000

Now, subtract the first equation from the second equation.

10y=49000

Divide both sides of the equation by 10

y=4900

Now, subtract this number from 8500 to find the amount of $10 tickets.

8500-4900=3600

The jazz concert sold 3600 $10 tickets and 4900 $20 tickets.

7 0
2 years ago
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