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3 years ago

Write an equation that defines the exponential function with base a > 0.

1 answer:

4 0

<span>The equation fpxq =ax defines an exponential function with base a. The domain of the function is all real numbers.</span>

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What is the slope of the line that passes through the points (−10,−8) and (−9,−8)? Write your answer in simplest form.

Alborosie

Answer:

slope=0

Step-by-step explanation:

3 0

2 years ago

Write the expression in factored form

olchik [2.2K]

$2.)\\ \\ n^2 - 9n +14 = 0 \\ \\ a=1 , \ b = -9, \ c = 14 \\ \\\Delta =b^2-4ac = (-9)^2 -4\cdot1\cdot 14 = 81 -56 = 25 \\ \\n_{1}=\frac{-b-\sqrt{\Delta} }{2a}=\frac{9-\sqrt{25}}{2 }=\frac{ 9-5}{2}=\frac{4}{2}= 2$

$n_{2}=\frac{-b+\sqrt{\Delta} }{2a}=\frac{9+\sqrt{25}}{2 }=\frac{ 9+5}{2}=\frac{14}{2}= 7 \\ \\ Answer : \ n^2 - 9n +14 =(n-2)(n-7)$

$3.)\\ \\ n^2 + 4n - 12 =0 \\ \\ a=1 , \ b = 4, \ c = -12 \\ \\\Delta =b^2-4ac = 4^2 -4\cdot1\cdot (-12) = 16+48=64 \\ \\n_{1}=\frac{-b-\sqrt{\Delta} }{2a}=\frac{-4-\sqrt{64}}{2 }=\frac{ -4-8}{2}=\frac{-12}{2}= -6$

$n_{2}=\frac{-b+\sqrt{\Delta} }{2a}= \frac{-4+\sqrt{64}}{2 }=\frac{ -4+8}{2}=\frac{4}{2}=2\\ \\ Answer : \ n^2 +4n -12 =(n+6)(n-2)$

second way :

$2.)\\ \\ n^2 - 9n +14 = n^2 - 9n+2n -2n +14 = n^2 - 7x -2n +14 =\\ \\ = n(n-7)-2(n-7)=(n-7)(n- 2)\\ \\ \\ Answer : \ n^2 - 9n +14 =(n-2)(n-7)$

$3.)\\ \\ n^2 + 4n - 12 = n^2 + 4n +2n - 2n - 12 = n^2 + 6n - 2n - 12 =\\ \\ = n(n+6) -2(n+6)=(n+6)(n-2) \\ \\ \\ Answer : \ n^2 +4n -12 =(n+6)(n-2)$

5 0

4 years ago

Read 2 more answers

If f(x) = 3x+2 and g(x) = x^2<br> what is g( f(x))

irakobra [83]

Answer:

$9x^{2}+12x+4$

Step-by-step explanation:

$g(f(x))=(3x+2)^{2}$

= $9x^{2}+12x+4$

6 0

4 years ago

For what valuels of x is the equation |4x + 2| = x + 8 TRUE?

dmitriy555 [2]

Answer:

$x=-2\quad \mathrm{or}\quad \:x=2$

Step-by-step explanation:

$|4x + 2| = x + 8 \\\\\mathrm{For\:each\:absolute\:find\:positive\:and\:negative\:intervals}\\\\\mathrm{Solve\:the\:inequality\:for\:each\:interval:}\\\\\mathrm{For\:}x$

5 0

3 years ago

Could someone please help me quickly? What are the ratios for sin, cos, & tan?

Anarel [89]

Answer:

Sin C: 7/25

Cos C: 25/24

Tan C: 7/24

Step-by-step explanation:

Sin C: Opposite/Hypotenuse

Cos C: Adjacent/Hypotenuse

Tan C: Opposite/Adjacent

6 0

3 years ago