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erica [24]
3 years ago
9

Which term best describes a creature with both human and robotic parts

SAT
1 answer:
MrRissso [65]3 years ago
4 0

Answer:

A human with both robotic and human parts is a Cyborg

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Which ion in the ground state has the same electron configuration as an atom of neon.
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38 Which ion in the ground state has the same electron configuration as an atom of neon in the ground state? (1) Ca2+ (2) Cl- (3) Li+ (4) O2-

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What is the second software layer of the Open Systems Interconnection reference model called?
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ramdom guess

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A good administrative position to acquire as a stepping stone to future position is
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A good administrative position to acquire as a stepping stone to future position is ADMINISTRATIVE OFFICER.

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Is this a good score on the sat test 680?
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If you got a 680 SAT score, you're probably wondering how you compare to other students, and whether a 680 is good enough to get into college.

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8 0
4 years ago
Read 2 more answers
Use the information above and the trigonometric identities to prove that Asin(wt
jenyasd209 [6]

Using sum and difference identities from trigonometric identities shows that; Asin(ωt)cos(φ) +Acos(ωt)sin(φ) =  Asin(ωt + φ)

<h3>How to prove Trigonometric Identities?</h3>

We know from sum and difference identities that;

sin (α + β) = sin(α)cos(β) + cos(α)sin(β)

sin (α - β) = sin(α)cos(β) - cos(α)sin(β)

c₂ = Acos(φ)

c₁ = Asin(φ)

The Pythagorean identity can be invoked to simplify the sum of squares:

c₁² + c₂² =

(Asin(φ))² + (Acos(φ))²

= A²(sin(φ)² +cos(φ)²)

= A² * 1

= A²

Using common factor as shown in the trigonometric identity above for Asin(ωt)cos(φ) +Acos(ωt)sin(φ) gives us;  Asin(ωt + φ)

Complete Question is;

y(t) = distance of weight from equilibrium position

ω = Angular Frequency (measured in radians per second)

A = Amplitude

φ = Phase shift

c₂ = Acos(φ)

c₁ = Asin(φ)

Use the information above and the trigonometric identities to prove that

Asin(ωt + φ) = Asin(ωt)cos(φ) +Acos(ωt)sin(φ)

Read more about Trigonometric Identities at; brainly.com/question/7331447

#SPJ1

8 0
2 years ago
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