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geniusboy [140]
2 years ago
11

The vertices of square cdef are c(1, 1), d(3, 1), e(3,−1) and f(1,−1). Which of the following shows that its diagonals are congr

uent perpendicular bisectors of each other?.
SAT
1 answer:
maks197457 [2]2 years ago
8 0

The equation -1 = -\frac {1}{1} shows that the diagonals are congruent perpendicular bisectors.

The vertices of the square are given as:

  • c = (1,1)
  • d = (3,1)
  • e =(3,-1)
  • f = (1,-1)

<h3>How to determine the congruent perpendicular bisectors.</h3>

Start by calculating the slope of diagonal ce using:

m = \frac{y_2 -y_1}{x_2  -x_1}

So, we have:

m = \frac{-1-1}{3  -1}

m = \frac{-2}{2}

m_1 = -1

Next, calculate the slope of diagonal df using:

m = \frac{y_2 -y_1}{x_2  -x_1}

So, we have:

m = \frac{-1-1}{1-3}

m = \frac{-2}{-2}

m_2 = 1

The slopes of both diagonals are:

m_1 = -1

m_2 = 1

By comparing both slopes, we have:

m_1 = -\frac {1}{m_2}

i.e.

-1 = -\frac {1}{1}

Hence, -1 = -\frac {1}{1} shows that the diagonals are congruent perpendicular bisectors.

Read more about perpendicular bisectors at:

brainly.com/question/11006922

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