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slega [8]
2 years ago
10

Find the volume of the trapezoidal prism

Mathematics
1 answer:
malfutka [58]2 years ago
4 0

Answer:

228 in³

Step-by-step explanation:

<u>Volume of a trapezoidal prism</u>

  • V = Area x height

<u>Finding Base Area (on the side here)</u>

  • A = 1/2 x (a + b) x h
  • A = 1/2 x (12 + 7) x 6
  • A = 3 x 19
  • A = 57 in²

<u>Volume</u>

  • V = A x h
  • V = 57 x 4
  • V = 228 in³
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Solve the quadratic equation by completing the square.x ^ 2 + 16x + 59 = 0First, choose the appropriate form and fill in the bla
nikitadnepr [17]

Given:

There are given the quadratic equation:

x^2+16x+59=0

Explanation:

To find the value of x by using completing the square, first, we need to subtract 59 on both sides of the given equation:

So,

From the given equation:

\begin{gathered} x^2+16x+59=0 \\ x^2+16x+59-59=0-59 \\ x^2+16x=-59 \end{gathered}

Now,

Take half of the x term and square it:

So,

From the x term,

\lbrack16\cdot\frac{1}{2}\rbrack^2=64

Then,

Add 64 on both sides of the above equation.

So,

\begin{gathered} x^2+16x=-59 \\ x^2+16x+64=-59+64 \\ x^2+16x+64=5 \\ (x+8)^2=5 \end{gathered}

Hence, an option first is correct:

(x+8)^2=5

Now,

From the above square:

\begin{gathered} (x+8)^2=5 \\ x+8=\pm\sqrt[]{5} \end{gathered}

Then,

Subtract 8 from both sides of the equation;;

So,

\begin{gathered} x+8=\pm\sqrt[]{5} \\ x+8-8=\pm\sqrt[]{5}-8 \\ x=\pm\sqrt[]{5}-8 \\ x=\sqrt[]{5}-8,\pm\sqrt[]{5}-8 \\ x=-5.7639,-10.236067 \end{gathered}

Final answer:

Hence, the value of x is shown below:

x=(-5.76,-10.24)

4 0
1 year ago
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Leya [2.2K]

Answer:

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Step-by-step explanation:

the angle 110 is equal to the opposite, so it remains with two angles that together get a (360-110-110=)140. so 140 in two is 70

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Zolol [24]

Answer:

<em>The rate of the equation is r when r is a constant</em>

Step-by-step explanation:

     We need to solve for the rate of the equation  

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     Differentiating on both sides with respect to time

     \frac{\mathrm{d} d}{\mathrm{d} t} = \frac{\mathrm{d} rt}{\mathrm{d} t}

      Considering r as a constant

       \frac{\mathrm{d} d}{\mathrm{d} t} =  r×\frac{\mathrm{d} t}{\mathrm{d} t}

      where, \frac{\mathrm{d} t}{\mathrm{d} t} = 1

       \frac{\mathrm{d} d}{\mathrm{d} t} = r

     <em>  The rate of the equation is r when r is a constant</em>

<em>        </em>

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