I don’t know how to do #8 HELP

Mathematics

1 answer:

horsena [70]3 years ago

7 0

Lets just look at each case and test them

1. (a^b)^(1/b)
This is the same as
a^b*1/b
which is
a^1 = a?
YES

2. (a^b)^b
a^2b = a?
NO

3. (a^b)/(a^b)
1 = a?
NO

4. (a^b)^(-1/b)
a^b*-1/b
a^-1 = a?
NO

The answer is number 1

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In the figure to the right, what is the measure of angle DAC ?

dem82 [27]

Answer:

47 degrees

Step-by-step explanation:

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7 0

3 years ago

Please help!!

yarga [219]

Because this is a fourth degree that will be tricky to factor as it is, we will do a u substitution. Let $x^2=u$ . We can now rewrite that polynomial in terms of u: $u^2-7u-8=0$ . Filling into the quadratic formula we have $u=\frac{7+/-\sqrt{49-4(1)(-8)}}{2}$ . Simplifying down $u=\frac{7+/-\sqrt{81}}{2}$ and $u=\frac{7+9}{2}$ or $u=\frac{7-9}{2}$ . That means that u = 8 or u = -1. But don't forget that we let $u=x^2$ , so we have to put x-squared back in for u. That gives us $x^2=8$ which simplifies down to $+/-2\sqrt{2}$ . That also gives us $x^2=-1$ . When we take the square root of -1, we have to use the fact that -1 = i^2, so we sub that in to get $x=+/-i$ . All in all, your solutions are as follows: $2\sqrt{2},-2\sqrt{2},i,-i$ which is choice b.