Question

PLEASE PLEASE HELP ITS MY FINAL GRADE PLEASE PLEASE

Answer 1

Answer:

See below

Step-by-step explanation:

Given there are 56 M&M's:

• Expected Value of Blue = 56(0.24) = 13.44
• Expected Value of Brown = 56(0.14) = 7.84
• Expected Value of Green = 56(0.16) = 8.96
• Expected Value of Orange = 56(0.20) = 11.20
• Expected Value of Red = 56(0.13) = 7.28
• Expected Value of Yellow = 56(0.14) = 7.84

Remember to use $np$ to calculate expected value! This will especially be helpful if you are conducting a chi-squared test of independence.