This following question is a sample question for brainliest on who has the correct answer with the best explanation. I do know t
he answer.
Note: * means multiply in the below equation:
What is
?
Note: * means multiply in the below equation:
What is
1 answer:
Answer:
What is 2/5 * 7/10
7/10 x 2/5 = 7/25
Step-by-step explanation:
As you Can See Here I have Explained how to Multiply Fraction.
we multiply two fractions, such as 7/10 x 2/5, we simply multiply the numerators by each other and the denominators by each other.
To multiply the two fractions, first multiply the top numbers by each other, then multiply the bottom numbers by each other,
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7/10 and 2/5 = ?
1. Multiply both numerators
7 x 2 = 14
2. Multiply both denominators
10 x 5 = 50
Which Equals 14/50
14/50 is an equivalent fraction for 7/10 times of 2/5, and its simplified term is 7/25.
Therefore Making the Answer 7/25.
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Answer:
1. {18, 18 , 19 , 19 , 19 , 20 , 21 , 21 , 21 , 21 , 23 , 24 , 24 , 26 , 27 , 27 , 29 , 30 , 30 , 30 , 33 , 33, 34 , 35 , 38 }
2a) md= 24 b) Q1=20.5 c) Q3= 30 3) Q3-Q1 =9.5 b) 19/48
Step-by-step explanation:
To answer this question the 1st and the 2nd we need to order the data entries. So from ordering from the lowest to the highest value:
1. {18, 18 , 19 , 19 , 19 , 20 , 21 , 21 , 21 , 21 , 23 , 24 , 24 , 26 , 27 , 27 , 29 , 30 , 30 , 30 , 33 , 33, 34 , 35 , 38 }
2. There are 25 entries.
{18, 18 , 19 , 19 , 19 , 20 , 21 , 21 , 21 , 21 , 23 , 24 , 24 , 26 , 27 , 27 , 29 , 30 , 30 , 30 , 33 , 33, 34 , 35 , 38 }
In odd quantities of observations, the Median equally separates it two parts.
md=24
b) To find out the 1st quartile, we can use this way:
Then 6.5 is between the 6th and 7th position. Let's find the mean of them, now:
c) Similarly toThe Third Quartile or Upper Quartile
The 19th position and 20th position average is:
3)
a) To find the Interquartile Range, we just need to find out the difference of the upper quartile and the lower one:Q_3-Q_1[/tex]
(30-20.5)=9.5
b) Interquartile Ratio is given by the quotient of the Interquartile Range over the Median
4) Since the Relative frequency Histogram asked is a one with 7 classes. Let's calculate how many values.
k=1+3.32logn
7=1+3.32logn
6=3.32logn
n≈66
Each class must have an interval of 10 ages, for (91-18)/7≈ 10. Notice the orange line intercepts the midpoint of each interval.
