Question

In ΔUVW, v = 63 cm, w = 49 cm and ∠U=161°. Find the area of ΔUVW, to the nearest square centimeter.

Answer 1

The area of the triangle UVW is the amount of space on the triangle

The area of the triangle UVW is 503 square centimeters

How to determine the area of the triangle

The given parameters are:

v = 63 cm, w = 49 cm and ∠U=161°

The area of the triangle is then calculated as:

$Area = \frac12 vw \sin(U)$

So, we have:

$Area = \frac12 * 63 * 49 * \sin(161)$

Evaluate the product

$Area = 503$

Hence, the area of the triangle UVW is 503 square centimeters

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brainly.com/question/10090807