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ivanzaharov [21]
2 years ago
8

____ uses a computer to design and test new products and modify existing ones. Computer-aided manufacturing Just-in-time design

Flexible manufacturing system Computer-aided design Materials resource planning
Computers and Technology
1 answer:
Tpy6a [65]2 years ago
5 0

Answer:

3D printing

Explanation:

You might be interested in
Write a program that asks the user to input a set of floating-point values. When the user enters a value that is not a number, g
Lady_Fox [76]

Answer:

Check the explanation

Explanation:

// include the necessary packages

import java.io.*;

import java.util.*;

// Declare a class

public class DataReader

{

// Start the main method.

public static void main(String[] args)

{

// create the object of scanner class.

Scanner scan = new Scanner(System.in);

// Declare variables.

boolean done = false;

boolean done1 = false;

float sum = 0;

double v;

int count = 0;

// start the while loop

while (!done1)

{

// start the do while loop

do

{

// prompt the user to enter the value.

System.out.println("Value:");

// start the try block

try

{

// input number

v = scan.nextDouble();

// calculate the sum

sum = (float) (sum + v);

}

// start the catch block

catch (Exception nfe)

{

// input a character variable(\n)

String ch = scan.nextLine();

// display the statement.

System.out.println(

"Input Error. Try again.");

// count the value.

count++;

break;

}

}

// end do while loop

while (!done);

// Check whether the value of count

// greater than 2 or not.

if (count >= 2)

{

// display the statement on console.

System.out.println("Sum: " + sum);

done1 = true;

}

}

}

}

Sample Output:

Value:

12

Value:

12

Value:

ten

Input Error. Try again.

Value:

5

Value:

nine

Input Error. Try again.

Sum: 29.0

3 0
3 years ago
Read 2 more answers
Write a program with a car's miles/gallon and gas dollars/gallon (both floats) as input, and output the gas cost for 10 miles, 5
omeli [17]

Answer:

The Following are the code to this question:

def cost(miles, milesPerGallon, dollarsPerGallon):##defining a method cost that accepts three parameter

   return miles / milesPerGallon * dollarsPerGallon# calculate cost and return it value  

milesPerGallon = float(input('Enter miles/Gallon value: '))#defining variable milesPerGallon for user input  

dollarsPerGallon = float(input('Enter dollars/ Gallon value: '))#defining variable dollarsPerGallon for user input

print('{:.5f}'.format(cost(10, milesPerGallon, dollarsPerGallon)))#call method and print its value

print('{:.5f}'.format(cost(50, milesPerGallon, dollarsPerGallon)))#call method and print its value

print('{:.3f}'.format(cost(400, milesPerGallon, dollarsPerGallon)))#call method and print its value

Output:

Enter miles/Gallon value: 20.0

Enter dollars/ Gallon value: 3.1599

1.57995

7.89975

63.198

Explanation:

In the above-given code, a method "cost" is defined, that accepts three value "miles, milesPerGallon, and dollarsPerGallon" in its parameter, and use the return keyword for calculating and return its value.

In the next step, two variable "milesPerGallon, and dollarsPerGallon" is declared, that use the input method with float keyword for input floating-point value.

After input value, it uses a print method with different miles values, which are "10,50, and 400", and input value to pass in cost method to call and print its return value.

5 0
3 years ago
Assume that a gallon of paint covers about 350 square feet of wall space. Create an application with a main() method that prompt
Makovka662 [10]

Answer:

<em>C++</em>

#include <iostream>

#include <cmath>

using namespace std;

///////////////////////////////////////////////////////////////////////

int noOfGallons(int wallArea) {

   int gallon = 350;

   int gallon_price = 32.0;

   float total_price = 0.0;

   ///////////////////////////////////////////

   float noOfGallons = (float)wallArea/(float)gallon;

   printf("No of gallons needed %.2f", noOfGallons);

   cout<<endl;

   //////////////////////////////////////////

  total_price = noOfGallons*gallon_price;

   return round(total_price);

}

int wallArea(int length, int width, int height) {

   int wall_area = length*width;

   int total_price = noOfGallons(wall_area);

}

///////////////////////////////////////////////////////////////////////

int main() {

   int length, width, height;

   ///////////////////////////////////////////

   cout<<"Enter length: ";

   cin>>length;

   

   cout<<"Enter width: ";

   cin>>width;

   

   cout<<"Enter height: ";

   cin>>height;

   

   cout<<endl;

   ///////////////////////////////////////////

   int total_price = wallArea(length, width, height);

  cout<<"Total price: $"<<total_price;

   ///////////////////////////////////////////

   return 0;

}

5 0
2 years ago
Most network cards contain a port that accepts a(n) ____, which looks similar to a telephone connector but is larger.
Vadim26 [7]
YOUR ANSWER IS -------- It accepts a RJ-45 connector
hope i helped you :).
take care
8 0
3 years ago
Consider the recursive method whose definition appear below. Why? public static String mysteryString (String s){ if(s.length()==
Marizza181 [45]

Answer:

retupmoc

Explanation:

1.) Anwser will be retupmoc

because

public static String mysteryString(String s){

if(s.length() == 1){

return s;

}

else{

return s.substring(s.length() -1) + mysteryString(s.substring(0, s.length()-1));

}

}

In this program input is "computer" . So the function mysteryString(String s) it does

return s.substring(s.length() -1) + mysteryString(s.substring(0, s.length()-1));

so when it enters the first time ??s.substring(s.length() -1) and it will be give you 'r' then it calls the function recursively by reducing the string length by one . So next time it calls the mysteryString function with string "compute" and next time it calls return s.substring(s.length()-1)? + mysteryString(s.substring(0,s.length-1)) so this time it gives "e" and calls the function again recursively . It keeps on doing till it matched the base case.

so it returns "retupmoc".

6 0
3 years ago
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