Answer:
class OddNumber
{
public static void main(String args[])
{
int n = 1000; //Store 1000 in Variable n typed integer
System.out.print("Odd Numbers from 1 to 1000 are:"); // Print headline of output window
for (int i = 1; i <= n; i++) //For loop to go through each number till end
{
if (i % 2 != 0) //check if number is even or odd.Not divisible by 2 without reminder means it is odd number
{
System.out.print(i + " "); //print odd numbers
}
}
}
}
Oh i do i do i do .... but could u retake the pic. it is kinda blurry
Answer:
bears = {"Grizzly":"angry", "Brown":"friendly", "Polar":"friendly"}
for bear in bears:
if bears[bear] == "friendly":
print("Hello, "+bear+" bear!")
else:
print("odd")
Explanation:
A dictionary called bears is given. A dictionary consists of key-value pairs.
You need to check each key-value pairs in bears and find the ones that have "friendly" as value using a for loop and if-else structure. In order to access the values of the dictionary, use the dictionary name and the key (inside the loop, the key is represented as bear variable). If a key has a value of "friendly", print the greeting. Otherwise, print "odd".
A. 5
b. as an unsigned int: 9. Normally a year is 365.25 days which would require 32-bits for an IEEE float.
c. 25
