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3 years ago

The coordinates of the vertexes of a triangle are A(3,3) B(6,6) C(9,3). What will be the new coordinates after a dilation

Mathematics

1 answer:

yuradex [85]3 years ago

8 0

Answer:

Step-by-step explanation:

Dilation by 3 from origin causes each point to be multiplied by 3.

(3,3) * 3 = (9, 9)

(6, 6) * 3 = (18, 18)

(9, 3) * 3 = (27, 9)

which is A

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The circumference of a circle is 22π in. What is the area, in square inches? Express your answer in terms of π

charle [14.2K]

Answer:

A = 121 pi in^2

Step-by-step explanation:

The circumference is given by

C = 2 * pi*r

22 pi = 2 * pi *r

Divide each side by 2 pi

22 pi / (2 pi) = 2 pi r / (2pi)

11 = r

Now find the area

A = pi r^2

A = pi (11)^2

A = 121 pi in^2

4 0

3 years ago

Given that lim x → 2 f ( x ) = 1 lim x → 2 g ( x ) = − 4 lim x → 2 h ( x ) = 0 limx→2f(x)=1 limx→2g(x)=-4 limx→2h(x)=0, find the

VashaNatasha [74]

Answer:

According what I can read, I have the following statements:

$\lim_{x \to 2} f(x) = 1$

$\lim_{x \to 2} g(x) = -4$

$\lim_{x \to 2} h(x) = 0$

a) Applying properties of limits

$\lim_{x \to 2} f(x) + 5g(x) = \lim_{x \to 2} f(x) + 5 \lim_{x \to 2} g(x) = 1 + 5*-4 = -19$

b) Applying properties of limits

$\lim_{x \to 2} g(x)^{3} = {(\lim_{x \to 2} g(x))}^{3} = (-4)^{3} = -64$

c) Applying properties of limits

$\lim_{x \to 2} \sqrt{f(x)} = \sqrt{\lim_{x \to 2} f(x)} = \sqrt{1} = 1$

d) Applying properties of limits

$\lim_{x \to 2} 4*g(x)*f(x) = 4*\lim_{x \to 2} g(x)*\lim_{x \to 2} f(x) = 4*-4*1 =-16$

e) Applying properties of limits

$\lim_{x \to 2} g(x)*h(x) = \lim_{x \to 2} g(x)*\lim_{x \to 2} h(x) = -4*0 =0$

f) Applying properties of limits

$\lim_{x \to 2} g(x)*h(x)*f(x) = \lim_{x \to 2} g(x)*\lim_{x \to 2} h(x)*\lim_{x \to 2} f(x = -4*0*1 =0$

3 0

4 years ago

Subtract five from three times a number and the result is equal to the number plus five. find the number.

allsm [11]

3(x)-5=x+5
3x=-5+5+x
3x=x
0=x
because 3x=x is basically would make each part into 0 which would end up the same.

6 0

4 years ago

You want to see if your dog will respond when you open the front door. After many attempts, you found that the dog barked 75% of

KatRina [158]

The dog barked 6 times

4 0

3 years ago

Classify each function as even, odd, or neither even nor odd.

drek231 [11]

The function

f(x) is even

g(x) is neither even nor odd

h(x) is odd

Steps:

for an even function it holds that f(-x) = f(x):

f(-x) = (-1)^6 x^6 - (-1)^4 x^ 4 = x^6 - x^4 = f(x) => f is even

for an odd h(x) it holds that h(-x) = -h(x):

$h(-x) = (-1)^5x^5-(-1)^3x^3 = -(x^5-x^3) = -h(x) \implies h(x)\,\, \mbox{even}$

It is easy to show that g(x) does not match any of the two possibilities above.

8 0

3 years ago

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