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2 years ago

Drag each expression to show whether the expression is equivalent to 35x−20, 40x+16, or neither.

Mathematics

2 answers:

kvasek [131]2 years ago

6 0

Answer:

4(10x+4) ⇒ 40x + 16

2(8+20x) ⇒ 40x + 16

5(7x-4) ⇒ 35x - 20

5(-4+7x) ⇒ 35x - 20

2(10x+8) ⇒ 20x + 16 Neither

Step-by-step explanation:

Given Expression:

4(10x+4)

2(8+20x)

5(7x-4)

5(-4+7x)

2(10x+8)

Solve:

4(10x+4) ⇒ 40x + 16 {4 · 10x = 40} {4 · 4 = 16}

2(8+20x) ⇒ 40x + 16 {2 · 8 = 16 } {20 · 2 = 40x}

5(7x-4) ⇒ 35x - 20 { 5 · 7x = 35x} {5 · - 4 = -20}

5(-4+7x) ⇒ 35x - 20 { 5 · -4 = -20 } {5 · 7x = 35x}

2(10x+8) ⇒ 20x + 16 {2 · 10x = 20x} { 2 · 8 = 16}

Hence,

4(10x+4) ⇒ 40x + 16

2(8+20x) ⇒ 40x + 16

5(7x-4) ⇒ 35x - 20

5(-4+7x) ⇒ 35x - 20

2(10x+8) ⇒ 20x + 16 Neither

Kavinsky

asambeis [7]2 years ago

3 0

Answer:

the ones that you would drag on the 35x-20 should be 5(7x-4) and 5(-4+7x).

For the 40x+16 should be 4(10x+4) and 2(8+20x) and for the neither one it should be 2(10x+8) so hopefully that is the correct answer for all of them

Step-by-step explanation:

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