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3 years ago

Help me I don’t know what the answer is

Mathematics

2 answers:

weeeeeb [17]3 years ago

6 0

I'm head for heels for you, she drives me up to the wall, and cut to the chase are the 3 answers.

Step-by-step explanation:

These are examples of idioms because they are phrased so it's not taken literally.

Svetlanka [38]3 years ago

3 0

Step-by-step explanation:

Idioms are phrases that aren't meant to be taken literally.

So the idioms are:

I'm head over heels for you

She drives me up the wall

Cut to the chase

You might be interested in

Solve |2x - 5| = 4. {x | x = -4.5 or x = 4.5} {x | x = 0.5 or x = 4.5} {x | 0.5 < x < 4.5}

kotykmax [81]

Answer:

{x | x = 0.5 or x = 4.5}

Explanation:

Before we begin, remember that:

The modulus gives the positive value of what's inside it.

This means that:

|a| = |-a| = a

Now, for the given, we have:

|2x-5| = 4

From the above rule, we can deduce that:

either:

2x - 5 = 4

2x = 4 + 5 = 9

x = 4.5 ............> first solution

Or:

2x - 5 = -4

2x = 5-4 = 1

x = 0.5 ..........> second solution

Now, we check:

at x = 4.5: |2(4.5)-5| = |9-5| = |4| = 4 ..........> first solution verified

at x = 0.5: |2(0.5)-5| = |1-5| = |-4| = 4 .........> second solution verified

Hope this helps :)

6 0

3 years ago

Chef Rita Is cooking for a Sunday brunch.She knows that 22 pancakes can feed 8 people.She is wondering how many people she can f

AlexFokin [52]

Answer:

Chef Rita can feed 20 people with 55 pancakes.

Step-by-step explanation:

We can solve this problem using equivalent ratios. Since we know that Chef Rita can feed 8 people with 22 pancakes, we can set up the ratio:

$\frac{22pancakes}{8people}=\frac{22}{8}$

To solve how many people she would be able to feed with 55 pancakes, we can set ratios equal to each other and solve for 'x' which is the number of people.

$\frac{22}{8}=\frac{55}{x}$

We can see what factor we multiply 22 by to get 55 and then we multiply the denominator by the same factor to get our equivalent ratio. 55 ÷ 22 = 2.5. So, 8 x 2.5 = 20 people.

4 0

3 years ago

Read 2 more answers

let sin(θ) =3/5 and tan(y) =12/5 both angels comes from 2 different right trianglesa)find the third side of the two tringles b)

statuscvo [17]

In a right triangle, we haev some trigonometric relationships between the sides and angles. Given an angle, the ratio between the opposite side to the angle by the hypotenuse is the sine of this angle, therefore, the following statement

$\sin (\theta)=\frac{3}{5}$

Describes the following triangle

To find the missing length x, we could use the Pythagorean Theorem. The sum of the squares of the legs is equal to the square of the hypotenuse. From this, we have the following equation

$x^2+3^2=5^2$

Solving for x, we have

$\begin{gathered} x^2+3^2=5^2 \\ x^2+9=25 \\ x^2=25-9 \\ x^2=16 \\ x=\sqrt[]{16} \\ x=4 \end{gathered}$

The missing length of the first triangle is equal to 4.

For the other triangle, instead of a sine we have a tangent relation. Given an angle in a right triangle, its tanget is equal to the ratio between the opposite side and adjacent side.The following expression

$\tan (y)=\frac{12}{5}$

Describes the following triangle

Using the Pythagorean Theorem again, we have

$5^2+12^2=h^2$

Solving for h, we have

$\begin{gathered} 5^2+12^2=h^2 \\ 25+144=h^2 \\ 169=h^2 \\ h=\sqrt[]{169} \\ h=13 \end{gathered}$

The missing side measure is equal to 13.

Now that we have all sides of both triangles, we can construct any trigonometric relation for those angles.

The sine is the ratio between the opposite side and the hypotenuse, and the cosine is the ratio between the adjacent side and the hypotenuse, therefore, we have the following relations for our angles

$\begin{gathered} \sin (\theta)=\frac{3}{5} \\ \cos (\theta)=\frac{4}{5} \\ \sin (y)=\frac{12}{13} \\ \cos (y)=\frac{5}{13} \end{gathered}$

To calculate the sine and cosine of the sum

$\begin{gathered} \sin (\theta+y) \\ \cos (\theta+y) \end{gathered}$

We can use the following identities

$\begin{gathered} \sin (A+B)=\sin A\cos B+\cos A\sin B \\ \cos (A+B)=\cos A\cos B-\sin A\sin B \end{gathered}$

Using those identities in our problem, we're going to have

$\begin{gathered} \sin (\theta+y)=\sin \theta\cos y+\cos \theta\sin y=\frac{3}{5}\cdot\frac{5}{13}+\frac{4}{5}\cdot\frac{12}{13}=\frac{63}{65} \\ \cos (\theta+y)=\cos \theta\cos y-\sin \theta\sin y=\frac{4}{5}\cdot\frac{5}{13}-\frac{3}{5}\cdot\frac{12}{13}=-\frac{16}{65} \end{gathered}$