Question

In 1985, the average ACT score was 18 with a standard deviation of 6. Also in 1985, the average SAT score was

Answer 1

The ACT score was better since the z-score of the ACT is greater than the z-score of the SAT. Then the correct option is B.

What is a normal distribution?

It is also called the Gaussian Distribution. It is the most important continuous probability distribution. The curve looks like a bell, so it is also called a bell curve.

The z-score is a numerical measurement used in statistics of the value's relationship to the mean of a group of values, measured in terms of standards from the mean.

The z-score is given as

$\rm z = \dfrac{x - \mu }{\sigma}$

In 1985, the average ACT score was 18 with a standard deviation of 6.

Also in 1985, the average SAT score was 500 with a standard deviation of 100.

Dr. Robertson took both tests in 1985 and scored a 26 on the ACT and a 620 on the SAT.

Then the z-score of the ACT will be

$\rm z = \dfrac{26 - 18}{6}\\\\z = 1.3333$

Then the z-score of the SAT will be

$\rm z = \dfrac{620 - 500}{100}\\\\z = 1.2$

Then the ACT score was better since the z-score of the ACT is greater than the z-score of the SAT.

More about the normal distribution link is given below.

brainly.com/question/12421652

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