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ankoles [38]
1 year ago
10

In 1985, the average ACT score was 18 with a standard deviation of 6. Also in 1985, the average SAT score was

Mathematics
1 answer:
lord [1]1 year ago
6 0

The ACT score was better since the z-score of the ACT is greater than the z-score of the SAT. Then the correct option is B.

<h3>What is a normal distribution?</h3>

It is also called the Gaussian Distribution. It is the most important continuous probability distribution. The curve looks like a bell, so it is also called a bell curve.

The z-score is a numerical measurement used in statistics of the value's relationship to the mean of a group of values, measured in terms of standards from the mean.

The z-score is given as

\rm z = \dfrac{x - \mu }{\sigma}

In 1985, the average ACT score was 18 with a standard deviation of 6.

Also in 1985, the average SAT score was 500 with a standard deviation of 100.

Dr. Robertson took both tests in 1985 and scored a 26 on the ACT and a 620 on the SAT.

Then the z-score of the ACT will be

\rm z = \dfrac{26 - 18}{6}\\\\z = 1.3333

Then the z-score of the SAT will be

\rm z = \dfrac{620 - 500}{100}\\\\z = 1.2

Then the ACT score was better since the z-score of the ACT is greater than the z-score of the SAT.

More about the normal distribution link is given below.

brainly.com/question/12421652

#SPJ1

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