Answer:
18.84 ft
Step-by-step explanation:
The formula for the circumference of a circle is C = πd or C = 2πr
We will use C = 2πr since we have r given in the photo
- We just need to substitute our values into the formula:
- C = 2(3.14)(3) = 18.84 ft
The y intercept in the equation is -2. What is your question?
8 x/3 apply the formula x power/root. Hope that helped!
Answer:
Total number of kilometers in the ride = 5 km
Number of kilometers Garret has already biked = k km
Number of kilometers Garret left to ride = 5 - k km
Number of minutes Garret takes per kilometer = 4 minutes.
Step-by-step explanation:
1. It takes 4 minutes for Garret to go a kilometer. Then
Number of minutes Garret takes per kilometer = 4 minutes.
2. Suppose the variable 
is the number of kilometers Garret has already biked.
3. Garret is partway through a 20-minute bike ride. It takes 4 minutes for him to go a kilometer. Then
Total number of kilometers in the ride is
4. Suppose the variable is the number of kilometers Garret has already biked. Then 
km is the number of kilometers Garret left to ride.
Answer:
Answer:
Since the calculated value of t= -1.340 does not fall in the critical region , so we accept H0 and may conclude that the data do not provide sufficient evidence to indicate hat there is difference in mean carbohydrate content between "meals with potatoes" and "meals with no potatoes".
Step-by-step explanation:
Potatoes : No Potatoes : Difference Difference (d)²
(Potatoes- No Potatoes)
29 41 -12 144
25 41 -16 256
17 37 -20 400
36 29 -7 49
41 30 11 121
25 38 -13 169
32 39 -7 49
29 10 19 361
38 29 9 81
34 55 -21 441
24 29 -5 25
27 27 0 0
<u>29 31 -2 4 </u>
<u> ∑ -64 2100 </u>
- We state our null and alternative hypotheses as
H0 : μd= 0 and Ha: μd≠0
2. The significance level alpha is set at α = 0.01
3. The test statistic under H0 is
t= d`/sd/√n
which has t distribution with n-1 degrees of freedom.
4. The critical region is t > t (0.005,12) = 3.055
5. Computations
d`= ∑d/n = -64/ 13= -4.923
sd²= ∑(di-d`)²/ n-1 = 1/n01 [ ∑di² - (∑di)²/n]
= 1/12 [2100- ( -4.923)] = 175.410
sd= √175.410 = 13.244
t = d`/sd/√n= - 4.923/13.244/√13
t= - 4.923/3.67344
t= -1.340
6. Conclusion :
Since the calculated value of t= -1.340 does not fall in the critical region , so we accept H0 and may conclude that the data do not provide sufficient evidence to indicate hat there is difference in mean carbohydrate content between "meals with potatoes" and "meals with no potatoes".
