Let W and L be width and length of the rectangular pen respectively.
Therefore,
Circumference, C = 2W+2L= 130 yd
Area, A = LW = 1050 yd^2=> L = 1050/W
Using the circumference expression and substituting for L;
130 = 2W + 2(1050/W) = 2W+2100/W
130*W = 2W*W + 2100
130W = 2W^2 +2100
2W^2-130W+2100 = 0
Solving for W;
W= [-(-130)+/- Sqrt ((-130)^2-4(2)(2100)]/2*2 = 32.5+/- 2.5
W = 30 or 35 yd
When W = 30, L = 1050/30 = 35
When W = 35, L = 1050/35 = 30
Therefore, W = 30 yd and L = 35 yd.
Answer:
The answer is 44.84. I dont actually see the correct answer here.
Step-by-step explanation:
The formula for the surface area of a square pyramid is a√(a2 + 4h2). In your pyramid a=4, and h=3. This gives 44.84 as the answer.
90 kilograms and gained weight at a constant rate.after 8 months ,he weighed 138 kilogramsin equation formy = mx + b138 = m(8) + 90solve for m
m = ( 138 - 90)/ 8m = 6 kg / month is the rate on which the young sumo wrestler gaining weight
