First question:
interest rate is 5% annually. After 4 years relative value of interest will be 1.05^4
Now we multiply that with starting funds and get
4000* 1.05^4 = 4862.03
Second question:
Because interest is 8% semiannually that means that after 35 years relative value of interest will be 1.04^(35*2)
6000*1.04^70 = 93,429.71
Third question:
after first year tractor's value will be 0.86*15450. After 3 years its value will be:
(0.86)^3*15,450 = 9,827.07
4a.4²x +3=1
Slotuion:
4²x + 3=1 : <em>x</em>= -⅛ (Decimal:<em>x</em>= -0.125)
Steps
4² x +3=1
4²=16
16x + 3=1
Subract 3 from borh sides
16x +3-3=1-3
Simplify
16x=-2
Divides both sides by 16
![\frac{16 \times }{16} = [tex] \frac{ - 2}{16}](https://tex.z-dn.net/?f=%20%5Cfrac%7B16%20%5Ctimes%20%7D%7B16%7D%20%3D%20%3C%2Fp%3E%3Cp%3E%5Btex%5D%20%5Cfrac%7B%20-%202%7D%7B16%7D%20)
[/tex]
Simplitfy
Simplify
<em>x</em> = -⅛
therefore the answer is <em>x</em><em>=</em><em> </em><em>-</em><em>⅛</em>
4b.ex-1 -5 =5
x~=3.30258
explanation:
e^(x-1)-5=5
e^(x-1)=10
x-1=ln 10
x-1~=2.30258
x~=3.30258
Answer:
Step-by-step explanation:
4^(4-7+1) = 4^-2
Answer:
cant see the picture dude
Step-by-step explanation:
Answer:
f(4) = 1
Step-by-step explanation:
f(4) = what?
So if we know that x, aka 4, is technicially f is greater then 2, so you can plug in x as 4. So that means 5(4) - 19 = 20 - 19 = 1, so f(4) = 1
