Question

A geneticist claims that four species of fruit flies should appear in the ratio

Answer 1

There are sufficient evidences which are of 5% significance level to reject the claim.

What is chi-square test?

A statistical test used to compare observed results with expected results is referred to as the chi-square test.

According to the given scenario,

• Ratio = 1:3:3:9
• Sample size = 2000
• Samples = 110, 345, 360, and 1185

To calculate:

Evidence to make conclusion to the geneticist's claim.

Total fruits = 1 + 3 + 3 + 9 = 16

As per the expected number of fruit flies

Each species = 1/16(2000) = 125.3/16(2000) = 375.3/16(2000) = 375.9/16(2000)

Each species = 1125

According to Chi-Square test -

$X^{2} =\epsilon\frac{(O_{i}-E_{i})^{2} }{E_{i}}$

$X^{2}$ = ( 110 - 125)²/125 + ( 345 - 375)²/375 + ( 360 - 375)²/375 + ( 1185 - 1125)²/1125

$X^{2}$ =  (15)²/125 + (30)²/375 + (15)²/375 + (60)²/1125

$X^{2}$ = 8

with df = 4 - 1 = 3, and  P( x² > 8) = 0.0460.

Thus, with a P-value, it is small, indicates 5% significance level to reject the claim.

For more details regarding the chi-square test, visit:

brainly.com/question/14082240

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