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2 years ago

6

Need help please answer ASAP!

2 answers:

9966 [12]2 years ago

3 0

Answer:

(2) B

Step-by-step explanation:

According to the graph

p(2, 3) so (-b, a) is (-3, 2)

So B is right

dezoksy [38]2 years ago

3 0

Answer:

$B = ( - b,\: a)$

Step-by-step explanation:

Since P has the coordinates (a, b), then (a,b) would be (2, 3). Therefore:

$a = 2\: and \: b = 3$

We are trying to find what point has the coordinates (-b, a). Recall:

$a = 2 \: \: \: \: \: \: \: \: b = 3 \\ ( - b, \: a) = \\ ( - 3, \: 2)$

The point that is at (-3, 2) is point B.

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Descried how to derive the quadratic formula from a quadratic equation in standard form

Aleks [24]

Answer:

The standard form of a quadratic equation is:

$ax^2+bx+c=0$ , $a\neq 0$

Quadratic Formula Derivation:

$ax^2+bx+c=0\\$

$x^2+\frac{b}{a}x+\frac{c}{a} =0$

$x^2+\frac{b}{a}x = -\frac{c}{a}$

Completing the Square:

$x^2+\frac{b}{a}x +\frac{b^2}{4a^2} = \frac{b^2}{4a^2}-\frac{c}{a}$

$( x+\frac{b}{2a} )^2 = \frac{b^2-4ac}{4a^2}$

Square Root property:

$x+\frac{b}{2a} = \pm \sqrt{ \frac{b^2-4ac}{4a^2}}$

$x = -\frac{b}{2a} \pm { \frac{\sqrt {b^2-4ac}}{2a}}$

$x = \frac{-b\pm\sqrt{b^2-4ac}} {2a} }$

8 0

3 years ago

Find the value of x<br> x=___

ss7ja [257]

Answer :

x = 2.8

Hope this helps!

4 0

3 years ago

Read 2 more answers

Which is the interval notation represent the domain?

Kazeer [188]

Answer:

The first choice, $(-\infty, 7) \cup (7, \infty)$ .

Step-by-step explanation:

The dashed vertical line is a vertical asymptote. The x-coordinate of all points on this vertical asymptote are equal to 7. In other words, when the x-value of a point on the graph approaches $7$ , its y-value approaches infinity (or negative infinity.)

Either way, the graph is not defined for $x = 7$ . The point $7$ should thus be excluded from the domain of the graph.

The graph is apparently defined for all other x-values. The domain of the function should thus be all real numbers with the exception of $x = 7$ . Here's how to write that in interval notation:

The set of all real numbers can be expressed as the interval $(-\infty, \infty)$ . Note that infinity $\infty$ (or $(- \infty)$ itself isn't a real number. The round brackets indicate that both endpoints are excluded from the from the interval.
The set of all real numbers less than (not equal to) $7$ is $(-\infty,7 )$ (both ends are excluded.) The set of all real numbers greater than (not equal to) $7$ is $(7, \infty)$ .
The set of all real numbers that is not equal to $7$ is the union of all real numbers less than $7$ and all real numbers greater than $7$ . The union operator $\cup$ connects two intervals.

In other words, the domain is $(-\infty, 7) \cup (7, \infty)$ .

5 0

3 years ago

Which function has zeros at x = 10 and x = 2?

Tasya [4]

Answer:

f(x) = x2 – 12x + 20

Step-by-step explanation:

if it has those zeros, then it is (x-10)(x-2)

if you multiply that out, you get x^2 - 12x +20

7 0

2 years ago

Supposed you are buying a triple deck ice cream cone with vanilla,strawberry,and chocolate as possible flavors. The flavors can

gizmo_the_mogwai [7]

Nine different cones can be made with these three flavor combinations.

3 0

3 years ago