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nlexa [21]
2 years ago
11

What is the square root of 68 ? i think it is 8.24 but i am not sure .

Mathematics
1 answer:
Andre45 [30]2 years ago
5 0
You are right ! It is 8.246 and so on ;)
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Please help me out! I tried to do it but I got it wrong.
Anika [276]

This may or may not be right.

You know that they are a graduate, and the total number of graduates are 2610.

The amount of graduates receiving financial aid is 1879.


The probability that a graduate student is on financial aid is: 1879/2610 = 0.7199 or 72%

4 0
3 years ago
The slope of (1, 5), (–3, 0) and (–2, 4), (3, 0)
chubhunter [2.5K]

Answer:

The slope of (1,5) and (-3,0) is 5/4

the slope of (-2,4) and (3,0) is -4/5

Step-by-step explanation:

5 0
3 years ago
Standard form of y+2=1/2(x-4)
gogolik [260]

y + 2 =  \frac{1}{2} (x - 4) \\ 2y + 4 = x - 4 \\  - x + 2y =  - 8
6 0
3 years ago
Read 2 more answers
A marketing firm would like to test-market the name of a new energy drink targeted at 18- to 29-year-olds via social media. A st
Anon25 [30]

Answer:

(a) The probability that a randomly selected U.S. adult uses social media is 0.35.

(b) The probability that a randomly selected U.S. adult is aged 18–29 is 0.22.

(c) The probability that a randomly selected U.S. adult is 18–29 and a user of social media is 0.198.

Step-by-step explanation:

Denote the events as follows:

<em>X</em> = an US adult who does not uses social media.

<em>Y</em> = an US adult between the ages 18 and 29.

<em>Z</em> = an US adult between the ages 30 and above.

The information provided is:

P (X) = 0.35

P (Z) = 0.78

P (Y ∪ X') = 0.672

(a)

Compute the probability that a randomly selected U.S. adult uses social media as follows:

P (US adult uses social media (<em>X'</em><em>)</em>) = 1 - P (US adult so not use social media)

                                                   =1-P(X)\\=1-0.35\\=0.65

Thus, the probability that a randomly selected U.S. adult uses social media is 0.35.

(b)

Compute the probability that a randomly selected U.S. adult is aged 18–29 as follows:

P (Adults between 18 - 29 (<em>Y</em>)) = 1 - P (Adults 30 or above)

                                            =1-P(Z)\\=1-0.78\\=0.22

Thus, the probability that a randomly selected U.S. adult is aged 18–29 is 0.22.

(c)

Compute the probability that a randomly selected U.S. adult is 18–29 and a user of social media as follows:

P (Y ∩ X') = P (Y) + P (X') - P (Y ∪ X')

                =0.22+0.65-0.672\\=0.198

Thus, the probability that a randomly selected U.S. adult is 18–29 and a user of social media is 0.198.

6 0
3 years ago
Beth made wristbands and belts for a craft sale. She sold 30 of these items. Each wristband sold for $5.50. Each belt sold at $8
baherus [9]

<u>✿</u><u>Answer:</u>

  • Both sold 18 wristbands and 12 belts

✂----------------------

Let, number of wristbands = x

number of belts = y

x+y=30  ➞ x~5.5

5.50x+8.75y=204 x1

5.50x+5.5y=165\\5.5x+8.75y=204\\---------\\-3.25y=-39

y=-39/3.25

y=12

x=30-12=18

So, Both~ sold ~18 ~wristbands ~and ~12~ belts.

❄❄❄❄❄❄

<h3>hope it helps...</h3><h3>have a great day!!</h3>
5 0
2 years ago
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