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nlexa [21]
3 years ago
11

What is the square root of 68 ? i think it is 8.24 but i am not sure .

Mathematics
1 answer:
Andre45 [30]3 years ago
5 0
You are right ! It is 8.246 and so on ;)
You might be interested in
John can clear a lot in 1.5 hours. His partner can do the same job in 4.5 hours. How long will it take them to clear the lot wor
Crank

Answer:

1 hour and 7.5 minutes

Step-by-step explanation:

We have the following information:

Jose makes 1 / 1.5 of the job per hour. It is his rate of work in addition to that the partner makes 1 / 4.5 of the job per hour. It is his rate of work.

Thus:

1 / 1.5 + 1 / 4.5 = 1 / x

0.8898 = 1 / x

x = 1 / 0.8888

x = 1.125

Hence, it will take 1 hour and 7.5 minutes for them to complete the job working together.

4 0
3 years ago
Debbie solved the linear equation 3(x + 4) − 2 = 16 as follows: between what lines did she make an error? line 1 and line 2 line
Drupady [299]
The question is not clear because the Debbie solution lines are not visible. Nevertheless,
The correct solution for this linear equation is the following:
<span>3(x + 4) − 2 = 16
</span><span>3(x + 4) = 16 + 2 
</span><span>3(x + 4) = 18
</span>(x + 4) = 18/3
(x + 4) = 6
x = 6 - 4
x = 2

3 0
4 years ago
What is 2x squared times by 4
mina [271]
Since you can only multiply the 2 and 4 together, you get 8x^2.
8 0
3 years ago
Pls help me with this question
choli [55]
$142.60 for all three employees
8 0
3 years ago
Can someone PLEASE help me solve this equation ? due soon
RideAnS [48]

\sf{Given : 3tanx + 7 = \dfrac{2}{(1 - sinx)(1 + sinx)}}

We know that : (a - b)(a + b) = a² - b²

\implies \sf{3tanx + 7 = \dfrac{2}{1 - sin^2x}}

We know that : 1 - sin²x = cos²x

\implies \sf{3tanx + 7 = \dfrac{2}{cos^2x}}

\sf{\bigstar \ \ We \ know \ that : \boxed{\sf{\dfrac{1}{cos^2x} = sec^2x}}}

\implies \sf{3tanx + 7 = 2sec^2x}

We know that : sec²x = 1 + tan²x

\implies \sf{3tanx + 7 =2(1 + tan^2x)}

\implies \sf{2 + 2tan^2x - 3 tanx - 7 = 0}

\implies \sf{2tan^2x - 3 tanx - 5 = 0}

\implies \sf{2tan^2x -  5tanx + 2tanx - 5 = 0}

\implies \sf{2tanx(tanx + 1) - 5(tanx + 1) = 0}

\implies \sf{(tanx + 1)(2tanx - 5) = 0}

\implies \sf{tanx = -1 \ (or) \ tanx = \dfrac{5}{2} }

8 0
3 years ago
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