Identify the coordinates of four points on the line with each given slope and y-intercept. slope = 2/3 and y-intercept = -5.....

Question

2 years ago

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....PLEASE ANSWER ASAP

1 answer:

alexdok [17] · Answer 1 · 2023-06-26T18:37:58+03:00

The linear equation is y = (2/3)*x - 5, and the 4 points in the graph are:

{ (-1, -17/3), (0, -5), (1, -13/3), (2, -11/3)}

<h3>How to identify the points on the line?</h3>

A linear equation written in the slope-intercept form is:

y = a*x + b

Where a is the slope and b is the y-intercept.

In this case, we have:

a = 2/3

b = -5

So our line is:

y = (2/3)*x - 5

To find the points, we need to evaluate the line in 4 different values of x.

We will use: x = -1, 0, 1, 2.

for x = -1 we have:

y = (2/3)*-1 - 5 = -2/3 - 5 = -17/3

So this gives the point (-1, -17/3).

for x = 0 we have:

y = (2/3)*0 - 5 = -5

So this gives the point (0, -5).

for x = 1 we have:

y = (2/3)*1 - 5 = -13/3

So this gives the point (1, -13/3).

for x = 2 we have:

y = (2/3)*2 - 5 = 4/3 - 15/3 = -11/3

So this gives the point (2, -11/3).

Then the 4 points are:

{ (-1, -17/3), (0, -5), (1, -13/3), (2, -11/3)}

If you want to learn more about linear equations:

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