Question

What is its length?

Answer 1

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$\large \sf \underline{Problem:}$

The perimeter of a rectangle is twice the

sum of its length and its width. The

perimeter is 40 meters and its length is 2

meters more than twice its width.

What is its length?

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$\large \sf \underline{Answer:}$

The answer is 12 m.

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$\large \sf \underline{Explanation:}$

The perimeter (P) of a rectangle is twice the sum of its length (I) and width (w):

P = 2(l + w) P = 34

=>> 2(1+w) = 34

1+ w = 34/2

⇒ I + w = 17

Length is 2 meters more than twice its width:

I = 2w + 2

Now we have the system of equations:

I + w = 17

I = 2w + 2

Use the substitution method and substitute I from the second equation into the first equation:

2w + 2 + w = 17

2w + w = 17 - 2

3w = 15

w = 15/3

w = 5

Now, substitute w into the equation:

I = 2w + 2

I =2* 5+2

I = 10 + 2

I = 12

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