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3 years ago

8

Which equation represents the data shown in the table provided in the image?

1 answer:

VladimirAG [237]3 years ago

4 0

The correct answer is A. y = 2x +1

Explanation:

An equation is a statement that shows equality. In this context, the equation should lead to two equal numbers even if the values of y and x change. In this context, the correct equation is y= 2X + 1 because this is the only one, in which, the value of Y is always equivalent to 2x + 1. To prove this, let's replace y and x for the values of the table.

First column

5 = 2 · 2 + 1

5 = 4 + 1

5 = 5

Second Column

9 = 2 · 4 + 1

9 = 8 + 1

9 = 9

Third column

13 = 6 · 2 + 1

13 = 12 + 1

13 = 13

Fourth column

17 = 8 · 2 + 1

17 = 16 + 1

17 = 17

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andrew-mc [135]

Answer:

Oils

Step-by-step explanation:

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2 years ago

DON’T SEND A LINK!<br><br> WHAT IS THE SLOPE OF THIS LINE<br><br> THE SLOPE IS NOT 4/1 OR 20/5

aleksandrvk [35]

Answer:

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2 years ago

Read 2 more answers

Simplify the following expression as much as you can use exponential properties. (6^-2)(3^-3)(3*6)^4

gtnhenbr [62]

Answer:

Simplifying the expression $(6^{-2})(3^{-3})(3*6)^4$ we get $\mathbf{108}$

Step-by-step explanation:

We need to simplify the expression $(6^{-2})(3^{-3})(3*6)^4$

Solving:

$(6^{-2})(3^{-3})(3*6)^4$

Applying exponent rule: $a^{-m}=\frac{1}{a^m}$

$=\frac{1}{(6^{2})}\frac{1}{(3^{3})}(18)^4\\=\frac{(18)^4}{6^{2}\:.\:3^{3}} \\$

Factors of $18=2\times 3\times 3=2\times3^2$

Factors of $6=2\times 3$

Replacing terms with factors

$=\frac{(2\times3^2)^4}{(2\times 3)^{2}\:.\:3^{3}} \\=\frac{(2)^4\times(3^2)^4}{(2)^2\times (3)^{2}\:.\:3^{3}} \\$

Using exponent rule: $(a^m)^n=a^{m\times n}$

$=\frac{(2)^4\times(3)^8}{(2)^2\times (3)^{2}\:.\:3^{3}} \\=\frac{2^4\times 3^8}{2^2\times 3^{2}\:.\:3^{3}}$

Using exponent rule: $a^m.a^n=a^{m+n}$

$=\frac{2^4\times 3^8}{2^2\times 3^{2+3}}\\=\frac{2^4\times 3^8}{2^2\times 3^{5}}$

Now using exponent rule: $\frac{a^m}{a^n}=a^{m-n}$

$=2^{4-2}\times 3^{8-5}\\=2^{2}\times 3^{3}\\=4\times 27\\=108$

So, simplifying the expression $(6^{-2})(3^{-3})(3*6)^4$ we get $\mathbf{108}$

7 0

3 years ago

In the adjoining figure O is the centre of the circle the tangent to the circle of radius 6 cm from the exterior point P of the

slamgirl [31]

Answer:

Let P be the external point. O be the origin. join O and P get OP and nearest point on the circle from P be A.

Let Q be the point onthe circle in which, tangent make 90° with radius at Q.

PQ = 8 and OQ = 6

we get a right angled triangle PQO right angled at Q.

so, OP^2 = OQ^2 + PQ^2= 8^2 + 6^2 = 64 + 36 =1==

therefore OP =10cm

we need nearest point from P, which is PA

PA = OP - OA= 10 -6=4cm

7 0

3 years ago

HELP PLEASEEEE!!! First correct answer gets brainliest!

RUDIKE [14]

Answer:

It is a solution

Step-by-step explanation:

y = -4x - 8

Let x = -9 and y = 28

Substitute these values in

28 = -4(-9) -8

28 = 36 -8

28 =28

This is true so it is a solution

5 0

3 years ago