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2 years ago

What is 50x23 divided by 4.

Mathematics

1 answer:

scoray [572]2 years ago

8 0

First multiply 50 x 23:

50 x 23 = 1,150

Now divide that by 4:

1150/4 = 287.5

answer: 287.5

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Where should 0.3% be placed in the Venn diagram?

Anit [1.1K]

Answer:

bottom

Step-by-step explanation:

7 0

3 years ago

A player in a game must roll a fair six-sided number cube and then flip a coin. What is the probability of a player rolling 4 an

expeople1 [14]

Answer:

Step-by-step explanation:

P(4) = 1/6

P(h) = 1/2

P(both) = 1/2 * 1/6 = 1/12

7 0

3 years ago

Solve this system by using substitution: y=7x-10 y=-3

Licemer1 [7]

Lets use substitution
y=7x-10
y=-3

so
-3=7x-10
7=7x
1=x

now lets check
y=7(1)-10
y=-3

therefore both equations have the same value

6 0

3 years ago

Farmer Jones raises ducks and cows. He looks out his window and sees 54 animals with a total of 122 feet. If each animal is “nor

Olenka [21]

Answer:

He have 47 ducks and 7 cows.

Step-by-step explanation:

Given:

Farmer Jones raises ducks and cows.

He looks out his window and sees 54 animals with a total of 122 feet.

Now, to find the each type of animal he have.

Let the number of ducks be $x.$

And the number of cows be $y.$

So, total number of animals are:

$x+y=54$

$x=54-y$ ....( 1 )

As, the feet of cows are 4 and ducks are 2.

Now, the total number of feet are:

$2(x)+4(y)=122$

$2x+4y=122$

Substituting the value of $x$ from equation (1) we get:

$2(54-y)+4y=122$

$108-2y+4y=122$

$108+2y=122$

Subtracting both sides by 108 we get:

$2y=14$

Dividing both sides by 2 we get:

$y=7.$

The number of cows = 7.

Now, to get the number of ducks we substitute the value of $y$ in equation (1):

$x=54-y\\x=54-7\\x=47.$

The number of ducks = 47.

Therefore, he have 47 ducks and 7 cows.

4 0

3 years ago

Find the center and radius of the circle with equation (x + 3)^2 + (y – 6)^2 = 100.

Sonja [21]

Answer:

center (-3,6)

radius(r) 10

Step-by-step explanation:

The center-radius form (it is really called standard form) of a circle is:

$(x-h)^2+(y-k)^2=r^2$

where $(h,k)$ is the center and $r$ is the radius.

Compare the following:

$(x-h)^2+(y-k)^2=r^2$

$(x+3)^2+(y-6)^2=100$

You should see the following:

$-h=3$

$-k=-6$

$r^2=100$ .

$-h=3 \text{ implies }h=-3$ .

$-k=-6 \text{ implies } k=6$ .

$r^2=100 \text{ implies } r=\sqrt{100}=10$ .

So the center is (-3,6) and the radius is 10.

6 0

3 years ago