Multiply 7x6 since when using pemdas, multiplication and division can be inverted, i.e. if multiplication is before division then you multiply and vice versa.
Hope this helps!
Answer:
A, C
Step-by-step explanation:
Actually, those questions require us to develop those equations to derive into trigonometrical equations so that we can unveil them or not. Doing it only two alternatives, the other ones will not result in Trigonometrical Identities.
Examining
A) True
![\frac{1-tan^{2}x}{2tanx} =\frac{1}{tan2x} \\ \frac{1-tan^{2}x}{2tanx} =\frac{1}{\frac{2tanx}{1-tan^{2}x}}\\ tan2x=\frac{1-tan^{2}x}{2tanx}](https://tex.z-dn.net/?f=%5Cfrac%7B1-tan%5E%7B2%7Dx%7D%7B2tanx%7D%20%3D%5Cfrac%7B1%7D%7Btan2x%7D%20%5C%5C%20%5Cfrac%7B1-tan%5E%7B2%7Dx%7D%7B2tanx%7D%20%3D%5Cfrac%7B1%7D%7B%5Cfrac%7B2tanx%7D%7B1-tan%5E%7B2%7Dx%7D%7D%5C%5C%20tan2x%3D%5Cfrac%7B1-tan%5E%7B2%7Dx%7D%7B2tanx%7D)
Double angle ![tan2\alpha =\frac{1 -tan^{2}\alpha }{2tan\alpha}](https://tex.z-dn.net/?f=tan2%5Calpha%20%3D%5Cfrac%7B1%20-tan%5E%7B2%7D%5Calpha%20%7D%7B2tan%5Calpha%7D)
B) False,
No further development towards a Trig Identity
C) True
Double Angle Sine Formula ![sin2\alpha =2sin\alpha *cos\alpha](https://tex.z-dn.net/?f=sin2%5Calpha%20%3D2sin%5Calpha%20%2Acos%5Calpha)
![sin(8x)=2sin(4x)cos(4x)\\2sin(4x)cos(4x)=2sin(4x)cos(4x)](https://tex.z-dn.net/?f=sin%288x%29%3D2sin%284x%29cos%284x%29%5C%5C2sin%284x%29cos%284x%29%3D2sin%284x%29cos%284x%29)
D) False No further development towards a Trig Identity
![[sin(x)-cos(x)]^{2} =1+sin(2x)\\ sin^{2} (x)-2sin(x)cos(x)+cos^{2}x=1+2sinxcosx\\ \\sin^{2} (x)+cos^{2}x=1+4sin(x)cos(x)](https://tex.z-dn.net/?f=%5Bsin%28x%29-cos%28x%29%5D%5E%7B2%7D%20%3D1%2Bsin%282x%29%5C%5C%20sin%5E%7B2%7D%20%28x%29-2sin%28x%29cos%28x%29%2Bcos%5E%7B2%7Dx%3D1%2B2sinxcosx%5C%5C%20%5C%5Csin%5E%7B2%7D%20%28x%29%2Bcos%5E%7B2%7Dx%3D1%2B4sin%28x%29cos%28x%29)
Answer:
A
Step-by-step explanation:
Because on a dice there are only 6 sides meaning there is a 1/6 chance of you to role a 4
Answer: T
Step-by-step explanation:
cuz i practice geometry.
This is what the graph would look like. Hope this helps:)