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Annette [7]
3 years ago
10

How to solve this equation equal to zero

Mathematics
1 answer:
hjlf3 years ago
8 0
3x² -16x-12 =0

We can solve this equation using formula.

a=3, b=-16, c=-12

x= \frac{-b+/- \sqrt{b^{2} -4ac} }{2a} 
\\ \\ x= \frac{16+/- \sqrt{16^{2}+4*3*12} }{2*3} = \frac{16+/- \sqrt{400} }{6} = \frac{16+/-20}{6} 
\\ \\ x_{1}= \frac{16+20}{6} =6
\\ \\x_{2}=  \frac{16-20}{6} =- \frac{4}{6} = -\frac{2}{3}
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x=4/f

Step-by-step explanation:

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If 83 : 45 :: 72 : ? solve and find the answer​
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Step-by-step explanation:

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Let unknown quantity (?) be x.

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83 : 45 :: 72 : x

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4 0
2 years ago
Vector A has a magnitude of 8.00 units and makes an angle of 45.0° with the positive x-axis. Vector B also has a magnitude of 8.
Burka [1]

Answer:

1) \bar A + \bar B = -2.34 i + 5.66 j

2) \bar A - \bar B = 13.66 i + 5.66 j

Step-by-step explanation:

Given:

IAI = 8.00 units  directed at angle of 45.0 degrees with +x - axis

IBI = 8.00 units  directed along -x - axis.

Components of vector along x and y directions:

A_x = (8.00) (cos(45.0^0)) = 5.66\\A_y = (8.00)(sin(45.0^0)) = 5.66

B_x = (8.00)(cos(180^0)) = -8.00\\B_y = (8.00)(sin(180^0)) = 0

\bar A = (A_x) i + (A_y) j = 5.66 i + 5.66 j\\\bar B = (B_x) i + (B_y) j = -8.00 i + 0 j

1) To find Vector sum ( \bar A + \bar B)

(\bar A + \bar B) = (5.66-8) i + ( 5.66+0) j = -2.34 i + 5.66 j

2) To find Vector sum (\bar A - \bar B)

(\bar A - \bar B) = (5.66-(-8)) i + ( 5.66-0) j = -13.66 i + 5.66 j

5 0
3 years ago
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